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4 years ago

Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.

Mathematics

1 answer:

xxTIMURxx [149]4 years ago

6 0

The area of the triangle is (1/2)(DE)^2*tan(60°) = (1/2)*2*√3 = √3.

Selection C is appropriate.

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Using the number 4236, how many numbers up to 20 does it divide without a reminder?

Minchanka [31]

Answer:

6 numbers it can be divided without a reminder. They are also even numbers.

5 0

3 years ago

What is obtained by squaring the standard deviation?

anastassius [24]

<h2>Answer:</h2>

Variance

<h2>Step-by-step explanation:</h2>

The standard deviation is related to the variance. The standard deviation measures the variation or dispersion of a set of data and is represented by the Greek letter sigma $\sigma$ , while the variance measures how far a set of numbers are spread out from their average value. The variance is obtained by squaring the standard deviation, so the variance can be found as $\sigma^{2}$

3 0

4 years ago

A printer needs to make a poster that will have a total of 500 cm2 that will have 3 cm margins on the sides and 2 cm margins on

goblinko [34]

Answer:

The largest printed area is 381.43 cm^2 .

Step-by-step explanation:

The width of the full poster = 500/x

Length of the printed area = l =x - 4

Width of the printed area = w = (500/x) - 2

Area of the printed space = (x - 4) × ((500/x) - 2)

Now, take derivative of the area

A' = (x - 4)×(-500/x^2) + ((500/x) - 2)

A' = (2000/x^2) - 2

A' = (2000-2x^2) / x^2

put derivative equal to zero like A' = 0

(2000-2x^2) / x^2 = 0

2000 = 2x^2

x^2 = 1000

x = 31.62

So, the length of the original poster is = x = 31.62 cm

The width of the full poster = 500/x = 15.81 cm

l = x - 4 = 27.62

w = 500/x - 2 = 13.81

Therefore, The area of space available for printing is = l × w

= 27.62 × 13.81 = 381.43 cm^2 .

5 0

3 years ago

What is first three common multiples of 4,9,and 12

wel

Answer:

36 is the answer of this question

4 0

3 years ago

Read 2 more answers

The length of the rectangle is 8cm longer than the width.

masya89 [10]

The length of the rectangle is 8cm longer than the width.
l=w+8
If the length of the original rectangle is increased by 6cm and the width is increased by 3cm the perimeter is 76cm.
p=76=((l+6)+(w+3))*2=(l+6+w+3)*2=(l+w+9)*2

to solve this substitute l=w+8 into the p= equation:
p=76=((w+8)+w+9)*2=
76=(2w+17)*2
76=4w+34
42=4w
10.5=w

l=w+8=10.5+8=18.5

4 0

4 years ago