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3 years ago

Which expression is equivalent to the following complex fraction? 1-1/x/2x

Mathematics

2 answers:

spin [16.1K]3 years ago

7 0

Answer:

(x-1) /2x

Step-by-step explanation:

(1-1/x)/2

(1 - 1/x) ÷ 2

copy dot flip for the division

(1 - 1/x) * 1/2

Getting a common denominator in the parentheses

(x-1)/x *1/2

(x-1) /2x

noname [10]3 years ago

5 0

Answer:

(x − 1) / (2x)

Step-by-step explanation:

I assume you mean (1 − (1/x)) / 2.

Find the common denominator of 1 and 1/x.

((x/x) − (1/x)) / 2

((x − 1) / x) / 2

Multiply by the reciprocal of 2.

((x − 1) / x) × (1/2)

(x − 1) / (2x)

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What is the median of the following numbers 45,36,52,55,47, 39

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Answer:

Step-by-step explanation:

By arranging the numbers from least to greatest, you can find the median by locating the central number in the data set.

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2 years ago

Victor has a bag of dimes and quarters. He has a total of 36 coins worth $5.40.

nata0808 [166]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0

2 years ago

Prove the polynomial identity. (2x−1)2+2(2x−1)=(2x+1)(2x−1) Drag and drop the expressions to correctly complete the proof of the

Alex_Xolod [135]

Answer:

Step-by-step explanation:

Given expression is,

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

To prove this identity we will take the left hand side of the equation and will prove equal to the right side.

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

4x² - 4x + 1 + 4x - 2 = (2x - 1)(2x + 1)

4x² - 1 = (2x - 1)(2x + 1)

(2x - 1)(2x + 1) = (2x - 1)(2x + 1) [Since a² - b² = (a - b)(a + b)]

6 0

3 years ago

F(x)= 3x+5....what is f(2)

arlik [135]

Answer:

the answer is 11

Step-by-step explanation:

3(2)+5=11

5 0

3 years ago