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Mumz [18]
3 years ago
9

A trader earns a profit of $60000 in 1998 and a profit of $75000 in 2003. Find the average rate of change of profit.

Mathematics
1 answer:
Feliz [49]3 years ago
8 0

Average rate of change of profit in five years that is from 1998 to 2003 is \$3000 per year.

<u>Solution:</u>

Given that

Trader earns a profit of \$60000 in 1998

Trader earns a profit of \$75000 in 2003

Need to determine average rate of change of profit.

Profit earned by Trader in 1998 let us assume \mathrm{P}_{98}=60000

Profit earned by Trader in 2003 let us assume \mathrm{P}_{03}=75000

Number of years between 1998 and 2003 let say t = 2003 – 1998 = 5 years  

\begin{aligned} \text { Average rate of change of profit } &=\frac{\text {Change in profit}}{\text {number of years}} \\\\ &=\frac{\mathrm{P}_{03}-\mathrm{P}_{98}}{t} \\\\ &=\frac{75000-60000}{5} \\\\ &=\frac{15000}{5}=3000 \end{aligned}

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3 years ago
0=-20.5x+16.35x-0.1245
Pachacha [2.7K]

The value of x in the given equation -20.5x+16.35x -0.1245 = 0\\ is 0.03

<u>Step-by-step explanation:</u>

The given equation is that -20.5x+16.35x -0.1245 = 0\\

<u>The steps to be followed to solve the equation are :</u>

Add the like terms together to reduce the equation in a simplified form.

Here, there are two x terms and they must be reduced to a single term.

For this, add the both terms together so that the equation is simplified into one x term and a constant term.

⇒ (-20.5x+16.35x) - 0.1245 = 0

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