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JulsSmile [24]
3 years ago
10

Solve the equation for W

Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

fourth option

Step-by-step explanation:

Given

\frac{2x-1}{y} = \frac{w+2}{2z} ( cross- multiply )

y(w + 2) = 2z(2x - 1) = 4xz - 2z ( divide both sides by y )

w + 2 = \frac{4xz-2z}{y} ( subtract 2 from both sides )

w = \frac{4xz-2z}{y} - 2

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Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste
lisabon 2012 [21]

Answer:

(a) The value of <em>x</em> is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

<em>R</em> = reported case of rabies is a raccoon

<em>F</em> = reported case of rabies is a fox

<em>B</em> = reported case of rabies is a bat

<em>O</em> = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = <em>x</em>.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, \sum P(X)=1

Compute the value of <em>x</em> as follows:

\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30

Thus, the value of <em>x</em> is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

P(A^{c})=1-P(A)

Compute the probability that a reported case of rabies is not a raccoon as follows:

P(R^{c})=1-P(R)\\=1-0.55\\=0.45

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0
3 years ago
Angela decides to recycle a large oatmeal container by using it to hold a friends birthday gift. Then she wraps the container in
Deffense [45]

Answer:

D. 135.37 in²

Step-by-step explanation:

We have that the gift paper consists of two circles and a square.

Thus, we will need to find the area of the circles and the square.

Now, as the diameter of the circle = 4 inches

So, the radius of the circle = \frac{4}{2} = 2 inches

Since, the area of a circle = \pi r^{2}

This implies that area of the two circles = 2\times \pi r^{2}

i.e. Area of the circles =  2\times \pi 2^{2}

i.e. Area of the circles =  8\pi

i.e. Area of the two circles = 25.133 in²

Further, one side of the square = 10.5 inches

Thus, the area of the square = side^{2}

i.e. Area of the square = 10.5^{2}

i.e. Area of the square = 110.25 in²

So, the overall area of the gift paper = 25.133 + 110.25 = 135.37 in².

Hence, the amount of paper used by Angela is 135.37 in².

7 0
3 years ago
Which is 9.5 expressed as a fraction in simplist form<br>A.19/2<br>B.46/5<br>C. 86/9<br>D.64/7​
WINSTONCH [101]

Answer:19/2

Step-by-step explanation:

19/2=9.5

Other are not in its very simplest form

8 0
3 years ago
What is the perimeter of the rectangle? <br>5 feet <br>6 feet <br>12 feet <br>X 36 feet​
shtirl [24]
It is 12 sense the perimeter is the outside of the square you have to add the 2 numbers by themselves because they are the same measurement and 5+5=10 1+1=2 10+2=12
6 0
3 years ago
Read 2 more answers
I really need help with this question ​
jenyasd209 [6]

Answer:

its a discrete graph

Step-by-step explanation:

hope this helps

5 0
3 years ago
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