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il63 [147K]
3 years ago
12

5/8 ? 2/5 would it be greater than, less or equal...plz help.

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0
5/8 would be greater than 2/5
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Find the x- and y- intercepts of the line 6x-2y=24 write your answers as ordered pairs
MrRissso [65]

Answer:

(4,0),(0,-12)

Step-by-step explanation:

7 0
3 years ago
Help please.<br><br><br> answer choices:<br> a)2/3<br> b)3/2<br> c)6/9<br> d)4/6
mr Goodwill [35]
The answer is It’s 3/2
7 0
2 years ago
Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor
Liula [17]

Answer:

(AD)^2 + (CD)^2 = (CA)^2 and (CD)^2 + (BD)^2 = (CB)^2

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

Hypothenuse = CA

Opposite = CD

Adjacent = AD

By Pythagoras Theorem, we have

(AD)^2 + (CD)^2 = (CA)^2

Considering CBD

From the attachment, we have that:

Hypothenuse = CB

Opposite = CD

Adjacent = BD

By Pythagoras Theorem, we have:

(CD)^2 + (BD)^2 = (CB)^2

4 0
3 years ago
Read 2 more answers
How many different four lettered codes can be formed if the first letter must be an S or a T
emmainna [20.7K]

Answer:

27,600

Step-by-step explanation:

We use the following formula:-  

Number of permutations of r from n

= nPr

= n! / (n-r)!

I am assuming you don't allow repeated letters in the 4 letter codes.

Take S as the first letter. Then we have 3 letters extra out of 25 letters.

Using the above formula the possible ways of doing this is

25! / (25 - 3)!

25! / 22!

= 25*24*23

= 13800.

The same number is obtained if the first letter is a T.

So the answer is 2*13800

= 27,600

8 0
3 years ago
Name:
lorasvet [3.4K]

Answer:

Make it shorter so i can help you

Step-by-step explanation:

5 0
3 years ago
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