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Aleks04 [339]
3 years ago
8

Loook at the image bellow <3 ill also give brainliest

Mathematics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

kinda late but the answer is B

Hope this helps!! <3

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What is the product?<br> (7x) (2x+5)(x2-4x-9)
babunello [35]
14x^2+35x


i think thats how u do it
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8 0
4 years ago
6. Solve each equation and check your solution. 3x - 6 = 4(2 - 3x) - 8x
Advocard [28]

Answer:

Multiple answers (Work & answers below)

Step-by-step explanation:

6 0
3 years ago
The quotient is 71 2/3 what is the divisor
zzz [600]
The answer to your question is 215
4 0
3 years ago
Read 2 more answers
–6 &lt; 2x – 4 &lt; 4 solve the inequality
Ira Lisetskai [31]

Answer:

The answer is

<h2>- 1 < x < 4</h2>

Step-by-step explanation:

<h3>- 6 < 2x - 4 < 4</h3>

First of all add 4 to both sides of the inequality to make 2x stand alone

That's

<h3>- 6 + 4 < 2x - 4 + 4 < 4 + 4 \\  - 2 < 2x < 8</h3>

Divide both sides of the inequality by 2 inorder to find x

That's

<h3>\frac{ - 2}{2}  <  \frac{2x}{2}  <  \frac{8}{2}</h3>

We have the final answer as

<h3>- 1 < x < 4</h3>

Hope this helps you

6 0
4 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
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