Answer:
The radius is 5 cm
Step-by-step explanation:
The formula for the area of a circle is : ![\p*radius^2](https://tex.z-dn.net/?f=%5Cp%2Aradius%5E2)
To work out the length of the radius you would first need to divide the area of 78.5 cm by pi (pi=3.14), this gives you
. This is because by dividing the area by pi we are isolating the value of the radius squared.
The final step is to work out the radius. You can do this by finding the square root of the radius squared which is 25, this gives you 5 cm. This means that the radius is 5 cm. This is because the square root is a number that when squared equals that number.
1) Divide 78.5 by pi.
![78.5/\pi=25cm^2](https://tex.z-dn.net/?f=78.5%2F%5Cpi%3D25cm%5E2)
2) Find the square root of 25 cm squared.
![\sqrt{25} =5 cm](https://tex.z-dn.net/?f=%5Csqrt%7B25%7D%20%3D5%20cm)
In this question pi is 3.14
Answer:
The answer would be greater since its being multiply the answer will always be greater than what you're multiplying.
Step-by-step explanation:
The product WILL be greater than the other two factors. When multiplying by a fraction the product is GREATER than the lesser factor.
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
log(x+3)(2x+3)+log( x+3)( x+5) =2
logx(2x+3)+3(2x+3 )+log x(x+5)+3(x+5)
![log {2x}^{2} + 3x + 6x + 9 + logx {}^{2} + 5x + 3x + 15](https://tex.z-dn.net/?f=log%20%7B2x%7D%5E%7B2%7D%20%20%2B%203x%20%2B%206x%20%2B%209%20%2B%20logx%20%7B%7D%5E%7B2%7D%20%20%2B%205x%20%2B%203x%20%2B%2015)