Answer: A.) Probability is approximately 5%
B.) probability that Die1 + Die + Die > 12 is approximately 26%
Step-by-step explanation:
Total possible outcomes of the three dies (sample space) = (6^3) = 216
For die1 + die2 + die3 to be equal six, then the number of outcomes which produces our required outcome from the sample space is = 6
Therefore, probability of die1 + die2 + die3 = 6 is given by;
P(die1 + die2 + die3 = 6) = total required outcome / total possible outcomes
P(die1 + die2 + die3 = 6) = 10/216
P( die1 + die2 + die3 = 6) = 0.04629
P( die1 + die2 + die3 = 6) = 4.63% approximately 5%
B) probability that Die1 + Die + Die > 12
P(Die1 + Die + Die > 12) = 57/216 = 0.2638
= 26.38%
Approximately 26%
