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3 years ago

Find the measure of a supplement of a 20 3/4 degrees

2 answers:

4 0

$20 \frac{3}{4}= \frac{83}{4} \\ \\ 180^{(4}-\frac{83}{4}= \frac{720-83}{4}=\boxed{\frac{637}{4}=159 \frac{1}{4}-the \ suplement}$

swat323 years ago

4 0

$supplement = 20 \ 3/4 + x =180
\\20 \ 3/4 + x =180
\\x = 180 - 20 \ 3/4
\\\boxed{x = 159.25}$

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PIT_PIT [208]

Answer:

B) 50

Step-by-step explanation:

min = 38

quartile 1 = 45

median = 50

quartile 3 = 67

maximum = 75

4 0

2 years ago

The quotient of a number and 15 is no greater than 450. what are the possible values for the number?

BartSMP [9]

Any numbers between 15 and 450 are possible values.

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3 years ago

a rectangular prism is 11 3/5 meters long and 9 meters wide and 12 1/2 meters high what is the volume in cubic meters of the pri

bazaltina [42]

Volume=legntht imes widht time height
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8 0

3 years ago

Read 2 more answers

Two solutions of differently concentrations of acid are mixed creating 40 mL of a soul union that is 32% acid one-quarter of the

AleksAgata [21]

Answer: Three quarters (30 ml) is made up of a 36% acid solution.

Step-by-step explanation:

Since we have given that

Total amount of solution = 40 ml

One- quarter of the solution is given by

$\frac{1}{4}\times 40\ ml\\\\=10\ ml$

Three-quarter of the solution is given by

$\frac{3}{4}\times 40\\\\=30\ ml$

According to question, we have

10 ml of solution is made up of = 20% of acid solution

30 ml of solution is made up of = say 'c ' of acid solution

40 ml of solution is made up of = 32 % of acid solution

So, our equation becomes,

$10\times 0.2+30\times c=40\times 0.32\\\\2+30c=12.8\\\\30c=12.8-2\\\\30c=10.8\\\\c=\frac{10.8}{30}\\\\c=0.36\\\\c=36\%$

Hence, three quarters (30 ml) is made up of a 36% acid solution.

5 0

3 years ago

It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How

omeli [17]

Number of child tickets bought is 20

<h3>Solution:</h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

Number of child tickets bought + number of adult tickets bought = 110

c + a = 110 ----- eqn 1

Also we can frame a equation as:

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

$c \times 5 + a \times 8 = 820$

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0

3 years ago