9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
Answer:
√97
Step-by-step explanation:
25 because Becky read 45 and Jason read 20
45-20 = 25
Answer:
7 (7/8)
Step-by-step explanation:
There
Answer:
6 (19 x - 2)
Step-by-step explanation:
Simplify the following:
6 - 3 (4 - 3 x) - 3 x - 6×9 x + 18×9 x - 6
-6×9 = -54:
6 - 3 (4 - 3 x) - 3 x + -54 x + 18×9 x - 6
18×9 = 162:
6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6
Grouping like terms, 6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6 = (-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6):
(-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6)
-3 x - 54 x + 162 x = 105 x:
105 x - 3 (4 - 3 x) + (6 - 6)
6 - 6 = 0:
105 x - 3 (4 - 3 x)
-3 (4 - 3 x) = 9 x - 12:
9 x - 12 + 105 x
Grouping like terms, 105 x + 9 x - 12 = (105 x + 9 x) - 12:
(105 x + 9 x) - 12
105 x + 9 x = 114 x:
114 x - 12
Factor 6 out of 114 x - 12:
Answer: 6 (19 x - 2)
