Which do you prefer COD 1 COD 2 or COD 3

Mathematics

2 answers:

mr Goodwill [35]3 years ago

8 0

Answer:

cod 3 my dude

marissa [1.9K]3 years ago

4 0

Cod 3 broooooooooooooooooooo

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H = 3 + 31t - 161²<br> Find all values of t for which the ball's height is 17 feet .

jasenka [17]

Answer:

t= 31/175 ≈ 5.64516129

Step-by-step explanation:

Refer Pic For Steps....

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2 years ago

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Illusion [34]

Answer:

x= -3

Step-by-step explanation:

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3 years ago

Read 2 more answers

Divide 2 over 3 ÷ 1 over 6 = ____.

Ad libitum [116K]

$\frac{2}{3} \div \frac{1}{6}$
{is the same as / equal to:}
$\frac{2}{3} \times \frac{6}{1} \\ = \frac{2}{3} \times 6 \\ = \frac{2 \times 6}{3} \\ = \frac{12}{3}$
{Simplify the fraction to become:}
$= 12 \div 3 \\ = 4$

Hope this helps! :)

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3 years ago

According to Descartes's rule of sign, how many possible positive and negative roots are there for the equation

damaskus [11]

<h2>Descartes Rule of Sign</h2><h3>Answer:</h3>

There are $3$ Real Roots for the Equation

<h3>Step-by-step explanation:</h3>

According to Descartes Rule of Sign, The maximum number of real roots a polynomial equation has is the number of times the sign of term changes from a higher power term to a lower power term.

In the given equation, $0=-4x^6-3x^5+2x^2-4x+1$ , we can already see that from $\red -4x^6$ to $\red -3x^5$ we can see that the sign didn't change so there might be no real roots. From $\red -3x^5$ to $\blue +2x^2$ , we can see that the signs change so we now know that there might be $1$ real root for equation. From $\blue +2x^2$ to $\red -4x$ , the signs changed so there might be $2$ real roots. From $\red -4x$ to $\blue +1$ , it changed again so there might be $3$ real roots. There are no other term with lesser power to compare for $\blue +1$ so we are left with $3$ real roots.