any of the 34 cars can finish first
any of the remaining 33 cars can finish second
any of the remaining 32 cars can finish third
Thus, the top 3 finishes can be done in (34)(33)(32) = 35904 ways
Answer:
x = 4 + sqrt(73) or x = 4 - sqrt(73)
Step-by-step explanation by completing the square:
Solve for x:
(x - 12) (x + 4) = 9
Expand out terms of the left hand side:
x^2 - 8 x - 48 = 9
Add 48 to both sides:
x^2 - 8 x = 57
Add 16 to both sides:
x^2 - 8 x + 16 = 73
Write the left hand side as a square:
(x - 4)^2 = 73
Take the square root of both sides:
x - 4 = sqrt(73) or x - 4 = -sqrt(73)
Add 4 to both sides:
x = 4 + sqrt(73) or x - 4 = -sqrt(73)
Add 4 to both sides:
Answer: x = 4 + sqrt(73) or x = 4 - sqrt(73)
Complete question :
There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.
Answer:
575 - 12t
Step-by-step explanation:
Given the following :
Total number of fireworks = 575
Number of shots per minute = 12
To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.
In algebraic terms
[total number of fireworks on display - (number of shots per minute × t)]
575 - 12t
Answer:
x=5y-35
Step-by-step explanation:
Answer:
Lauren
- 220
- 440
- 660
- 880
- 1100
- 1320
Harold
- 110
- 220
- 330
- 440
- 550
- 660
Step-by-step explanation:
Multiply values by the number of months.
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-Chetan K
