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diamong [38]
3 years ago
8

Find the equation of the circle: y-intercepts 4 and –8, contain (–12, –8)

Mathematics
1 answer:
laila [671]3 years ago
6 0

Answer:

  (x +6)^2 +(y +2)^2 = 72

Step-by-step explanation:

The given points are vertices of a right triangle. The circle circumscribing that triangle (through all 3 vertices) will have its center at the midpoint of the hypotenuse:

  ((0, 4) +(-12, -8))/2 = (-6, -2)

The equation of a circle with center (h, k) through point (a, b) is ...

  (x -h)^2 +(y -k)^2 = (a -h)^2 +(b -k)^2

For center (-6, -2) and point (0, 4), the equation is ...

  (x +6)^2 +(y +2)^2 = (0+6)^2 +(4 +2)^2

  (x +6)^2 +(y +2)^2 = 72

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Find the coordinates of the three points on the graph of y = (1/2)x² -2x whose x-values are −2, 0, and 4.
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Step-by-step explanation:

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