Add the following constants in the class definition, before the main method:
private final static float START_COST = 1.5f;
private final static float HIGH_TARIFF = 0.5f;
private final static float LOW_TARIFF = 0.25f;
private final static int FIXED_MINS = 2;
private final static int HIGH_TARIFF_MINS = 10;
Then add this to the main method you already had:
float price = START_COST;
if (x > FIXED_MINS) {
if (x <= HIGH_TARIFF_MINS) {
price += HIGH_TARIFF*(x-FIXED_MINS);
}
else {
price += HIGH_TARIFF*(HIGH_TARIFF_MINS-FIXED_MINS)
+ LOW_TARIFF*(x-HIGH_TARIFF_MINS);
}
}
System.out.printf("A %d minute call costs %.2f", x, price);
Answer:
for (int h = k; h >= 0; h--)
Explanation:
From the list of given options, option C answers the question.
In the outer loop
Initially, k = 0
In the inner loop,
h = k = 0
The value of h will be printed once because h>=0 means 0>=0 and this implies once
To the outer loop
k = 1
The inner loop will always assume value of k;
So,
h = 1
This will be printed twice because of the condition h>=0 means 1>=0.
Since 1 and 0 are >=0; 1 will be printed twice
To the outer loop
k = 2
The inner loop
h = 2
This will be printed thrice because of the condition h>=0 means 2>=0.
Since 2, 1 and 0 are >=0; 2 will be printed thrice
To the outer loop
k = 3
The inner loop
h = 3
This will be printed four times because of the condition h>=0 means 3>=0.
Since 3, 2, 1 and 0 are >=0; 3 will be printed four times
GrooveFunnels is a game-changer and it’s disrupting the market quite a bit.
Subdirectory
Have a great day! c:
