What is the area of the rhombus?
2 answers:
The area of rhombus is 24 square units.
Step-by-step explanation:
Given,
Length of one diagonal = p = 3+3 = 6 units
Length of other diagonal = q = 4+4 = 8 units
Area of rhombus =
Area of rhombus =
Area of rhombus =
Area of rhombus = 24 square units
The area of rhombus is 24 square units.
Keywords: rhombus, area
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Answer:
The values for expression is h = - 2 and k = 5
Step-by-step explanation:
Given algebraic expression can be written as :
2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k
Now opening the bracket
Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3 ) + k
Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12 +k
Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12 + k
Now, equating the equation both sides
I.e - 10 = ( h - 2 )
Or , h - 2 = - 10
I.e , h = - 10 + 2
∴ h = - 2
Again , 11 = ( 3 - 4 h )
or, 11 = 3 - 4 h
or, 11 - 3 = - 4 h
or, 8 = - 4 h
∴ h =
I.e h = - 2
Again
- 7 = - 12 + k
Or, k = - 7 + 12
∴ k = 5
Hence The values for expression is h = - 2 and k = 5 . Answer
Answer:
(i) Five number summary: Minimum value = 1, ,
,
, Maximum value = 26.
(ii) IQR = 2.5, upper fence = 24.25 and lower fence = 14.25.
(iii) 26 is an outlier of the data.
Step-by-step explanation:
The given data set is
19, 18, 23, 18, 18, 26, 19, 16, 20, 18, 17, 21
Arrange the data set in ascending order.
16, 17, 18, 18, 18, 18, 19, 19, 20, 21, 23, 26
Divide the data set in 4 equal parts.
(16, 17, 18), (18, 18, 18), (19, 19, 20), (21, 23, 26)
Minimum value = 16
Maximum value = 26
The inter quartile range (IQR) of the data is
Upper fence :
Lower fence :
If the any element of the data set lies out side the upper fence and lower fence, then it is called an outlier.
26 ∉ [14.25, 24.25]
Therefore, 26 is an outlier of the data.