The normal distribution curve for the problem is shown below
We need to standardise the value X=405.5 by using the formula


We now need to find the probability of z=0.32 by reading the z-table
Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

from the z-table, the reading

gives 0.6255
hence,

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%
Answer:
Mom=30 Daughter=6
Step-by-step explanation:
M=5×D
M+6=3×D
5D=3D-6
2D=6
D=12
M=12×3=36
Now: D=12-6=6
M=36-6=30
Divide 25 by 4 and you get 6 with a remainder of 1. That remainder of 1 can go over 4 to create the final answer of 6 and 1/4.
Answer:
he will at 14 bars i believe
Step-by-step explanation: