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3 years ago

If you reflect the image over the x - axis, what are the new coordinates of the shape?

Mathematics

1 answer:

lutik1710 [3]3 years ago

8 0

Greetings!

When reflecting a shape over the x-axis, you simply change the number to its opposite positive/negative equivalent.

This means that the new co-ordinates would be (-5,1) , (-5,4) and (-2,4).

Hope this helps!

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Solve this please show your work <3

Nookie1986 [14]

Given:

The expression is

$\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=$

To find:

The simplified form of the expression.

Solution:

We have,

$\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=$

The expression $\sqrt[3]{48}$ can be written as

$\sqrt[3]{48}=\sqrt[3]{8\cdot 6}$

$\sqrt[3]{48}=\sqrt[3]{8}\cdot \sqrt[3]{6}$ $[\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]$

$\sqrt[3]{48}=2\cdot \sqrt[3]{6}$

$\sqrt[3]{48}=2\sqrt[3]{6}$

Therefore, $\sqrt[3]{48}=\sqrt[3]{8\cdot 6}=2\sqrt[3]{6}$ .

5 0

2 years ago

When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent? Θ' = negative pi over 6; s

timama [110]

Answer:

Option C is correct.

Step-by-step explanation:

$\theta=\frac{5\pi }{6}$

We need to find reference angle and signs of sinФ, cosФ and tanФ

We know that $\theta=\frac{5\pi }{6}radians$ is equal to 150°

and 150° is in 2nd quadrant.

So, Ф is in 2nd quadrant.

And In 2nd quadrant sine is positive, while cos and tan are negative

The reference angle Ф' is found by: π - Ф

=> Ф = 5π/6

so, Reference angle Ф' = π - 5π/6

Ф' = 6π - 5π/6

Ф' = π/6

So, Option C Θ' = pi over 6; sine is positive, cosine and tangent are negative is correct.

5 0

3 years ago

Bdhxhdjjd helpppll & I’ll give you a star +15 points

ikadub [295]

X = -4

the slope is undefined as it only passes through the x-axis on -4.

6 0

2 years ago

What is the solution set of 7x 2 + 3x = 0? {0, 3/7} {0, -3/7} {0, -4/7}

34kurt

X(7x+3)=0
x=0
or
7x=-3
x=-3/7

so,
(0,0) or (-3/7,0)

5 0

2 years ago

The pyramid of khagra,in Egypt,is 488 feet tall. The Eiffel Tower,in France,is 1,063 feet tall. How much taller is the Eiffel To

steposvetlana [31]

Answer:

The Eiffel Tower in France is 575 feet taller than pyramid of khagra.

Step-by-step explanation:

We are given the following in the question:

Height of pyramid of khagra = 488 feet

Height of Eiffel Tower in France = 1,063 feet

Difference in height =

= Height of Eiffel Tower in France - Height of pyramid of khagra

$=1063 - 488\\= 575\text{ feet}$

Thus, the Eiffel Tower in France is 575 feet taller than pyramid of khagra.

7 0

2 years ago