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kupik [55]
3 years ago
14

Which of the following functions is graphed below?

Mathematics
2 answers:
velikii [3]3 years ago
7 0

Answer:  The correct option is (D)

y=\begin{array}{cc}\{ &\begin{array}{cc}x^2-4 & x\leq 1\\x^2+3 & x>1\end{array}\end{array}

Step-by-step explanation:  We are given to select the correct function that is graphed in the figure.

We have,

\textup{If }y=x^2-4,\textup{ then }y(1)=1^2-4=1-4=-3,\\\\\textup{If }y=x^2+3,\textup{ then }y(1)=1^2+3=1+3=4.

In the graph, there is closed hole at y = - 3, so y = - 3 (x = 1) is included.

Also, there is an open hole at y =  4, so y = 4 (x = 1) is excluded.

So, If y = x² - 4, then x will be greater than or equal to 1.

If y = x² + 3, then x will be less than 1.

Also,

\textup{for }x\leq 1,~~y\leq x^2-4,\\\\\textup{for }x> 1,~~y> x^2+3.

Therefore, the graphed function will be

y=\begin{array}{cc}\{ &\begin{array}{cc}x^2-4 & x\leq 1\\x^2+3 & x>1\end{array}\end{array}

Option (D) is the correct function.

ella [17]3 years ago
5 0

Answer:

Hi there!

Step-by-step explanation:

Is there anyway you can do a better picture of it please


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