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2 years ago

What’s the answer For this picture problem

Mathematics

1 answer:

Mazyrski [523]2 years ago

5 0

Answer:

x = 2/9

Step-by-step explanation:

1. -5x = -10/9 (original equation)

2. -5x*9 = (-10/9)*9 (multiply both sides by 9)

-45x = -10

3. -45x/-45 = -10/-45 (divide both sides by -45)

x = 10/45 (note that a negative number divided by a negative number is positive)

4. x = 2/9 (divide the numerator and denominator by 5 to simplify)

Therefor x = 2/9

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Find an equation in standard form for the ellipse that satisfies the given conditions. Major axis length 10 on y-axis minor axis

Helen [10]

The answe might be e= 10\16

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3 years ago

Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

$x=\sqrt{3}-1$

Square both sides:

$x^2=(\sqrt{3}-1)^2$

Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

$x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2$

$x^2=3-2\sqrt{3}+1$

$x^2=4-2\sqrt{3}$

Let's go back to the full $x^2-x+1$ .

$x^2-x+1$

$(4-2\sqrt{3})-(\sqrt{3}-1)+1$

$4-2\sqrt{3}-\sqrt{3}+1+1$

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

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3 years ago

Complete the square and wright in standard form x^2+y^2-8x-12+52=36

Sphinxa [80]

X² + y² - 8x - 12y + 52 = 36
x² - 8x + y² - 12y + 52 = 36
x² - 8x + y² - 12y = 88
(x² - 8x + 16) + (y² - 12y + 36) = 88 + 16 + 36
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(h, k) = (x, y) = (4, 6)

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3 years ago

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laiz [17]

Keywords

linear equation, variables

Step 1

Define the variables

Let

x-----> number of erasers

y-----> total cost

we know that

------> this is the linear equation that represent the situation

therefore

the answer is y = 0.84 + (0.38)x

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3 years ago

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Add.

Vikki [24]

Answer:

5/6

Step-by-step explanation:

9/30 + 16/30 = 25/30 = 5/6

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3 years ago

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