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Hitman42 [59]
3 years ago
9

What’s the answer For this picture problem

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

x = 2/9

Step-by-step explanation:

1. -5x = -10/9 (original equation)

2. -5x*9 = (-10/9)*9 (multiply both sides by 9)

-45x = -10

3. -45x/-45 = -10/-45 (divide both sides by -45)

x = 10/45 (note that a negative number divided by a negative number is positive)

4. x = 2/9 (divide the numerator and denominator by 5 to simplify)

Therefor x = 2/9

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How many terms are in this expression?<br><br> X + 1
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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
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\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

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x=-3,\:x=5,\:x=\frac{1}{2}

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