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Hitman42 [59]
3 years ago
9

What’s the answer For this picture problem

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

x = 2/9

Step-by-step explanation:

1. -5x = -10/9 (original equation)

2. -5x*9 = (-10/9)*9 (multiply both sides by 9)

-45x = -10

3. -45x/-45 = -10/-45 (divide both sides by -45)

x = 10/45 (note that a negative number divided by a negative number is positive)

4. x = 2/9 (divide the numerator and denominator by 5 to simplify)

Therefor x = 2/9

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find the numerical lengths of the diagonals of the parallelogram below where FB=4x-2 FD=3y-1 FC=3x and FA=3y-3. solve using a sy
Andre45 [30]

Answer:

BD = 28

AC = 24

Step-by-step explanation:

Diagonals of a parallelogram bisect each other.

4x − 2 = 3y − 1

3x = 3y − 3

Using elimination to solve the system of equations, subtract the second equation from the first.

(4x − 2) − 3x = (3y − 1) − (3y − 3)

4x − 2 − 3x = 3y − 1 − 3y + 3

x − 2 = 2

x = 4

Substitute into either equation to find y.

3(4) = 3y − 3

12 = 3y − 3

15 = 3y

y = 5

The length of BD is:

4(4) − 2 + 3(5) − 1 = 28

The length of AC is:

3(4) + 3(5) − 3 = 24

8 0
3 years ago
Anything will help please
svp [43]

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

Cos T = 17 / 19

Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

for example on question 7, to find the angle x they have given you the hypotenuse and the adjacent side so

cos x = 9 / 18

to find x plug: cos^-1 (9/18) in the calculator

8 0
2 years ago
Find the area of the triangle 14cm 25cm
Anna71 [15]

Answer:

175 cm

Step-by-step explanation:

assuming it's a right triangle, the formula used is A= (1/2)(base)(height)

so (1/2)(14)(25)

which equals 175

4 0
3 years ago
Which sequence of transformations proves that shape I is similar to shape II?
Serhud [2]

Answer:

B. a reflection across X axis and then a dilation by a scale factor of 1.5

Step-by-step explanation:

As clear from the graph all the coordinates of image 2 are 1.5 times of image 1 so shape 2 is dilated by the scale factor 1.5.

It is evident from the graph that lines AO and A"O"are parallel to each other so shape 2 is the reflection of shape 1.

Now we calculate the magnitude of line AB

m1 = (y2-y1)/(x2-x1)

    =(-3+6)/(-4.5=9)

    =3/4.5

    =1/1.5

    =2/3

Next we calculate magnitude m2 of A"B"  

m2= (2-4) /(-3+6)

     =(-2/3)

Then we know Tan(180-∅) = -tan∅

similarly if m1=(-m2)

then the one line having magnitude m2 is the rotated image through X axis by 180° of the line having magnitude m1.

So the answer is B.

4 0
4 years ago
Read 2 more answers
Agnes scored 87 on the first test 73 on the second test, 81 on the third test. supoise Agbes has one more test in the semester a
castortr0y [4]
87+73+81+x=4*80, find x
6 0
3 years ago
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