For the function f(x) = 2x+2, what is the new function and reflection for-f(x)?
1 answer:
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The average velocity of the object after during the first three seconds is: 48m/s
The time at which the instantaneous velocity equals the average velocity within the first three seconds is 1.5 seconds.
<h3>What is instantaneous and average velocities?</h3>Instantaneous velocity is the speed of an object at a particular point in time.
Average velocity is the velocity of an object after covering a certain distance for a period of time
Analysis:
Given
initial height = 600 feet
Height with respect to time = f(t) = -16 + 600
a) Height at t = 0 = 600 feet
Height at t = 3 seconds = f(3) = -16 + 600 = 456 feet
Distance travelled = 600 - 456 = 144 feet
Average velocity = distance travelled/time taken = 144/3 = 48 feet/seconds
b) instantaneous velocity at time t = =
= -32t
when instantaneous velocity equal average velocity
-32t = -48
t = 1.5 seconds
In conclusion, the Average velocity after 3 seconds is 48 feet per seconds and the time taken for the average velocity to equal the instantaneous velocity is 1.5 seconds.
Learn more about instantaneous and Average velocity: brainly.com/question/13372043
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So hmmmmm, notice... the boat went up in 3hrs, came back to the starting point in 2hrs, it went up 108km, it came back, well, from 108km to distance 0, so the distance on the way back is just the same 108km
now... let's say the stream has a speed rate of "r", and the boat has a still water speed rate of "b"
bear in mind that, when the boat is going UP, is not really going "b" fast, because the stream's "r" rate is going against it, and thus subtracting "r" from "b", so is really going " b - r " fast
when the boat is going down, is not going "b" fast either, because, again the stream's rate "r" is adding to it, because is going with the current, so is really going " b + r " fast
now, recall your d =rt, distance = rate * time
solve for "r"
what's b? well, 36+ r = b
now... let's say the stream has a speed rate of "r", and the boat has a still water speed rate of "b"
bear in mind that, when the boat is going UP, is not really going "b" fast, because the stream's "r" rate is going against it, and thus subtracting "r" from "b", so is really going " b - r " fast
when the boat is going down, is not going "b" fast either, because, again the stream's rate "r" is adding to it, because is going with the current, so is really going " b + r " fast
now, recall your d =rt, distance = rate * time
solve for "r"
what's b? well, 36+ r = b