The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
false
Step-by-step explanation:
if is 6= you need to time by it self like: 6×6=is ur answer
Answer: question 1: 20 question 2: 21 question 3: 17, 19, 23
Step-by-step explanation:
Answer:
(5,6)
Step-by-step explanation:
-6x+6y=6
-6x + 3y =-12
Multiply the first equation by -1
6x-6y=-6
Add this to the second equation
6x-6y=-6
-6x + 3y =-12
---------------------
-3y = -18
Divide each side by -3
-3y/-3 = -18/-3
y =6
Now we need to find x
6x - 6y = -6
6x -6(6) = -6
6x -36 = -6
Add 36 to each side
6x-36+36 = -6+36
6x = 30
Divide each side by 6
6x/6 = 30/6
x =5
