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Eva8 [605]
3 years ago
14

If Angle AOC =85 and angle BOC=2x+10 and angleAOB=4x-15 find the degress measure of BOC and AOB

Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

m angle BOC 120

m angle AOB 205

Step-by-step explanation:

So you are given mangle AOC+mangle BOC=mangle AOB.

mangle means measure of angle.

Let's do some substituting into our equation.

85+2x+10=4x-15

Solve for x... First I'm going to combine the like terms on the left hand side:

95+2x=4x-15

Add 15 on both sides

110+2x=4x

Subtract 2x on both sides

110     =2x

Divide both sides by 2

110/2   =x

x         =110/2

x          =55

So Recall mangle BOC=2x+10   =2(55)+10=110+10=120

And you also have mangle AOB=4x-15=4(55)-15=220-15=205

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If two lines have the same slope, they are _______.
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Answer:

same slope is parallel lines

Step-by-step explanation:

4 0
3 years ago
What are the coordinates of point B?
zaharov [31]

Point a is at (-2,4) => (x1,y1)

Midpoint is (2.5, 3.5) => (a,b)

Point B is (x2, y2)

To find midpoint we use formula

(a=\frac{x_1+x_2}{2} , b= \frac{y_1+y_2}{2})

a= 2.5, b= 3.5, x1= -2  and y1= 4

Plug in all the values and findout x2, y2

(2.5=\frac{-2+x_2}{2} , 3.5= \frac{4+y_2}{2})

multiply 2 on both sides to remove fraction

(5 = -2+x2 , 7 = 4+ y2)

5 = -2+x2, so x2= 7

7 = 4+ y2, so y2= 3

The point B is ( 7, 3)

3 0
3 years ago
The profit per acre from a grove of orange trees is given by x(190 − x) dollars, where x is the number of orange trees per acre.
nasty-shy [4]

Answer:

P(x) = 190 x -x^2

In order to maximize the last equation we can derivate the function in term of x and we got:

\frac{dP}{dx} = 190 -2x

And setting this derivate equal to 0 we got:

\frac{dP}{dx} = 190 -2x=0

And solving for x we got:

x = 95

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

P(x=95)= 95(190-95)= 95*95 = 9025

Step-by-step explanation:

For this case we have the following function for the profit:

P(x) = x(190-x)

And we can rewrite this expression like this:

P(x) = 190 x -x^2

In order to maximize the last equation we can derivate the function in term of x and we got:

\frac{dP}{dx} = 190 -2x

And setting this derivate equal to 0 we got:

\frac{dP}{dx} = 190 -2x=0

And solving for x we got:

x = 95

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

P(x=95)= 95(190-95)= 95*95 = 9025

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B2%7D%5E%7Bx%20%2B%202%7D%20-%20%20%7B2%7D%5E%7B%20x%20%2B%203%7D%20%7D%7B%2
weeeeeb [17]

I suppose you just have to simplify this expression.

(2ˣ⁺² - 2ˣ⁺³) / (2ˣ⁺¹ - 2ˣ⁺²)

Divide through every term by the lowest power of 2, which would be <em>x</em> + 1 :

… = (2ˣ⁺²/2ˣ⁺¹ - 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ - 2ˣ⁺²/2ˣ⁺¹)

Recall that <em>n</em>ª / <em>n</em>ᵇ = <em>n</em>ª⁻ᵇ, so that we have

… = (2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺³⁾ ⁻ ⁽ˣ⁺¹⁾) / (2⁽ˣ⁺¹⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾)

… = (2¹ - 2²) / (2⁰ - 2¹)

… = (2 - 4) / (1 - 2)

… = (-2) / (-1)

… = 2

Another way to get the same result: rewrite every term as a multiple of <em>y</em> = 2ˣ :

… = (2²×2ˣ - 2³×2ˣ) / (2×2ˣ - 2²×2ˣ)

… = (4×2ˣ - 8×2ˣ) / (2×2ˣ - 4×2ˣ)

… = (4<em>y</em> - 8<em>y</em>) / (2<em>y</em> - 4<em>y</em>)

… = (-4<em>y</em>) / (-2<em>y</em>)

… = 2

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3 years ago
The baker pays $0.80 per pound for sugar and $1.25 per pound for butter. Which of the following equations shows t, how much the
Lynna [10]

Answer:

(6 x $1.25) + (20 x $0.80)

5 0
2 years ago
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