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Eva8 [605]
3 years ago
14

If Angle AOC =85 and angle BOC=2x+10 and angleAOB=4x-15 find the degress measure of BOC and AOB

Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

m angle BOC 120

m angle AOB 205

Step-by-step explanation:

So you are given mangle AOC+mangle BOC=mangle AOB.

mangle means measure of angle.

Let's do some substituting into our equation.

85+2x+10=4x-15

Solve for x... First I'm going to combine the like terms on the left hand side:

95+2x=4x-15

Add 15 on both sides

110+2x=4x

Subtract 2x on both sides

110     =2x

Divide both sides by 2

110/2   =x

x         =110/2

x          =55

So Recall mangle BOC=2x+10   =2(55)+10=110+10=120

And you also have mangle AOB=4x-15=4(55)-15=220-15=205

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What is the equation of a line, in general form, with a slope of -2 and a y-intercept of 8? 1.    1x + 2y - 8 = 0       2. 2x +
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3 years ago
Hey can you please help me posted picture of question
Deffense [45]
Correct answer is option D.

The solution is listed below

F(x)=4x+7 \\  \\ 
y=4x+7 \\  \\ 
y-7=4x \\  \\ 
 \frac{y-7}{4}=x \\  \\ 
 x= \frac{y-7}{4} \\  \\ 
f-^{1}(y) = \frac{y-7}{4} \\  \\ 
f-^{1}(x) = \frac{x-7}{4} \\  \\ 

6 0
3 years ago
The length of a rectangle is 3 more than 3 times its width. The perimeter of the rectangle is 174 inches. What is the length of
saveliy_v [14]

Answer:

<em>l = w + 3cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:</em>

I hope this helps you.

5 0
3 years ago
The school band collected $2,892 for 480 tickets sold to their spring concert. Adult tickets were $8 each and student tickets we
kakasveta [241]
A + s = 480......s = 480 - a
8a + 5s = 2892

8a + 5(480 - a) = 2892
8a + 2400 - 5a = 2892
8a - 5a = 2892 - 2400
3a = 492
a = 492/3
a = 164 <=== there were 164 adult tickets sold
5 0
4 years ago
Read 2 more answers
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