$- \sqrt[3]{2 x^{4} y^{2} } *3 \sqrt[3]{20 x^{5}y } =-3 \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} = \\ \\ =-3 \sqrt[3]{40 x^{9} y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9} y^{3} } = \\ \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} } \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}$
Answer: B.

6 0

3 years ago

Hey can someone tell me what -3x^2(14x^2-2x-8) equals

Ad libitum [116K]

Answer:

-42x^4 + 6x^3 + 24x^2

Step-by-step explanation:

8 0

2 years ago

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Factorise and evaluate<br><br> 25 × 6 + 25 × 4

AlekseyPX

Answer:

250

Step-by-step explanation:

First with factorise the common factor out first, in this case, its 25.

25x6+25x4 = 25(6+4)

Now using of order of operations we will evaluate the bracket first.

25(6+4) = 25(10) = 25 x 10 = 250

6 0

1 year ago

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