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pychu [463]
3 years ago
11

There are many four-digit positive integers in which the product of the digits is equal to $5!$. What is the sum of the largest

and smallest such four-digit numbers
Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

7

Step-by-step explanation:

5! = 1×2×3×4×5

they want 4 numbers that = 120

so

2x3x4x5 = 120

2 + 5 = 7

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HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
MA_775_DIABLO [31]

Answer:

m<3 = 97

m<10 = 97

m<9 = 83

m<5 = 97

m<7 = 83

m<16 = 97

Step-by-step explanation:

m<3 = m<2 because of vertical angles

m<10 = m<2 because of corresponding angles

m<9 + 97 = 180

m<9 = 83

m<5 + 83 = 180

m<5 = 97

m<7 = m<6 because of vertical angles

m<16 = m<5 because of alternate exterior angles.

4 0
3 years ago
What is 9n=1(98-2n) equal to? Id really appreciate if you could answer both though
borishaifa [10]
N=32/3as a fraction alternative form is n=10.6
5 0
2 years ago
Which shosws the commutative property of multiplication?
Dahasolnce [82]
B. 5.5×(7.5×6.4) =(5.5×7.5)×6.4
3 0
3 years ago
What is 4/15 / -3.4<br>​
seraphim [82]

Answer:

Factor the numerator and denominator and cancel the common facotors which would give you 0.07843137

4 0
3 years ago
5t=24.5 what does t represent
Inessa [10]
Divide both sides by 5 to get t by itself, then you have your answer
4 0
4 years ago
Read 2 more answers
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