Calculate the mass 9f the earth, assuring that uts is sphere with radius 6.67×10^6m.

Physics

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

6.86 × 10²⁴ kg

Explanation:

The mass of the earth m = density of earth, ρ × volume of earth, V

m = ρV

The density of the earth, ρ = 5515 kg/m³ and since the earth is a sphere, its volume is the volume of a sphere V = 4πr³/3 where r = radius of the earth = 6.67 × 10⁶ m

Since m = ρV

m = ρ4πr³/3

So, substituting the values of the variables into the equation for the mass of the earth, m, we have

m = 5515 kg/m³ × 4π(6.67 × 10⁶ m)³/3

m = 5515 kg/m³ × 4π × 296.741 × 10¹⁸ m³/3

m = 5515 kg/m³ × 1189.9639π × 10¹⁸ m³/3

m = 6546105.64378π × 10¹⁸ kg/3

m = 20565197.400122 × 10¹⁸ kg/3

m = 6855065.8 × 10¹⁸ kg

m = 6.8550658 × 10²⁴ kg

m ≅ 6.86 × 10²⁴ kg

You might be interested in

Using the lensmaker's formula (equation (5) of your lab manual), calculate the index of refraction of the acrylic lens. You shou

uysha [10]

Answer:

n = 1 + R / f

Explanation:

The equation of the constructor is optical is

1 / f = 1 / p + 1 / q

where f is the focal length, p and q are the distance to the object and image, respectively

The exercise tells us that it is a concave lens with focal length fo, in these lenses the focal length is negative. The relationship to calculate the focal length is

1 / f = (n -n₀) (1 /R₁ - 1 /R₂)

where is n₀ the refractive index of the medium that surrounds the lens in this case it is air with n₀ = 1, you do not indicate the type of lens, but the most used lens is the concave plane, in this case R₂ = ∞, so which 1 / R₂ = 0, let's substitute

1 / f = (n-1) / R₁

n - 1 = R₁ / f

let's calculate

n = 1- R₁ / f

remember that the radius of curvature is negative, so the equation is

n = 1 + R / f

8 0

3 years ago

In its elemental state, carbon is available as:

stich3 [128]

I believe the answer is coal

8 0