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vichka [17]
3 years ago
9

The Bohr radius a0 is the most probable distance between the proton and the electron in the Hydrogen atom, when the Hydrogen ato

m is in the ground state. The value of the Bohr Radius is: 1 a0 = 0.529 angstrom. One angstrom is 10-10 m. What is the magnitude of the electric force between a proton and an electron when they are at a distance of 2.63 Bohr radius away from each other?
Physics
1 answer:
katen-ka-za [31]3 years ago
3 0

Answer:

The electric force is  F =  11.9 *10^{-9} \ N

Explanation:

From the question we are told that

    The  Bohr radius at ground state is  a_o  =  0.529 A =  0.529 ^10^{-10} \ m

    The values of the distance between the proton and an electron  z =  2.63a_o

The electric force is mathematically represented as

     F  =  \frac{k * n  * p }{r^2}

Where n and p are charges on a single electron and on a single proton which is mathematically represented as

      n = p  =   1.60 * 10^{-19} \ C

    and  k is the coulomb's  constant with a value

           k =9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.

substituting values

       F =  \frac{9*10^{9} *  [(1.60*10^{-19} ]^2)}{(2.63 * 0.529 * 10^{-10})^2}

         F =  11.9 *10^{-9} \ N

     

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