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Mathematics

1 answer:

alina1380 [7]2 years ago

3 0

Answer:

$39

Step-by-step explanation:

Using the given formula :

I = P × R × T

I = 30 × 10/100 × 3

I = $9

She have = 30 + 9 = $39

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Hey can you please help me posted picture of question

JulijaS [17]

Answer: 32

Explanation:

The number of leaves in a tree diagram for probabilities is equal to the number of possible outcomes.

Tossing a coin 5 times leads to these results:

First,second, third and fourth tossing are the nodes; and fifth tossing has the leaves.

Root → 2 nodes → 2² nodes → 2³ nodes → 2⁴ → 2⁵ leaves = 32

Those 32 leaves is this sample space:

head-head-head-head-head
head-head-head-head-tail

head-head-head-tail-head
head-head-head-tail-tail

head-head-tail-head-head
head-head-tail-head-tail

head-head-tail-tail-head
head-head-tail-tail-tail

head-tail-head-head-head
head-tail-head-head-tail

head-tail-head-tail-head
head-tail-head-tail-tail

.......... (continue)

And so on until you have included all the possibilities, ending with tail-tail-tail-tail-tail. Those will be 32 outcomes.

7 0

2 years ago

Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be ac

Likurg_2 [28]

For this problem, the most accurate is to use combinations

Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are $nC_r = \frac{ n! }{r! (n-r)!}$

n represents the amount of things you can choose and choose r from them

You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

$P = \frac{_{117}C_3}{_{120}C_3}$

Where $_{117}C_3$ is the number of ways to select 3 non-defective components from 117 non-defective components and $_{120}C_3$ is the number of ways to select 3 components from 120.