Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
0.8 x 103 because the first number cant be less then 1 or more then 9 you would have to move the decimal to make the equation correct
To evaluate the expression all you have to do is substitute the value for the variable.
3 + y + 6, y = 5
3 + 5 + 6
8 + 6
14.
The solution is 14.
13/17 is at the lowest because they are both prime numbers.
Answer: 3/2
Step-by-step explanation:
Let's consider the points (6,9) and (4,6).
The difference in the y coordinates is 3, and the diffeence in the x coordinates is 2.
So, the slope is 3/2.