The line has a positive slope. Let's look at all the slopes:
1) -3
2) -3
3) 3
4)3
Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.
The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.
1) y = -3/2x - 5/2
2) y = -3/2x + 5/2
We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.
The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.
Answer:
$10.10
Step-by-step explanation:
25x² + 1 = 5
25x² + 1 - 5 = 0
25x² - 4 = 0 By difference of two squares
(5x)² - (2)² = 0
(5x - 2)(5x + 2) = 0
5x - 2 = 0 or 5x + 2 = 0
5x = 0 + 2 5x = 0 - 2
5x = 2 5x = -2
x = 2/5 x = -2/5
x = 0.4 x = -0.4
x = + 0.4 or -0.4