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sdas [7]
4 years ago
10

What is (-3/4)x(7/8)

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
3 0
-0.65625 or -21/32 should be your answer just cross multiply
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Jenny has $1,200 in her savings account. If the bank pays 3% interest per year on savings, how much interest does she earn in on
Strike441 [17]

Given:

Principal value = $1200

Rate of interest = 3% per year

To find:

The interest earned by Jenny in one year.

Solution:

Formula of interest:

I=\dfrac{P\times r\times t}{100}

Where, P is principal, r is rate of interest and t is time.

We have, P = 1200, r = 3, t=1. Putting these values, we get

I=\dfrac{1200\times 3\times 1}{100}

I=\dfrac{3600}{100}

I=36

The interest earned by Jenny in one year is $36.

Therefore, the correct option is A.

7 0
3 years ago
Please help, I will give brainliest. I am struggling badly.
alekssr [168]

Answer:

B because the line crosses the y axis at 4  and the slope will be -1 because the line is going downhill which therefore makes it negative

hope it helps:)

Step-by-step explanation:

3 0
3 years ago
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What are the correct answers for these problem's
Maru [420]
The answer is B. About 83 g
4 0
4 years ago
What is the solution to the equation log(2x — 7) = log(5х + 2)?<br> NEEED ANSWER ASAP
slavikrds [6]

Answer:

"No Solution"

Step-by-step explanation:

We can use the log property shown below to simplify this:

Log(a)=Log(b)\\Means\\a=b

Since no "base" is given, we take base as "10" and use property to write:

2x-7=5x+2

Now, we solve for x:

2x-7=5x+2\\5x-2x=-7-2\\3x=-9\\x=-3

But we are NOT done. We have to take the value and put it into the equation to check if there is any NEGATIVE value, because we cannot take negative log.

Putting in LHS:

Log(2x - 7)

Log(2(-3) - 7)

Log(-6-7)

Log(-13)

This can't be solved. So x = -3 is not a solution. Thus, there is NO SOLUTION to the equation given.

3 0
4 years ago
According to the diagram, point B lies on how many faces of the pyramid? three one two four
Alisiya [41]

Answer:

it lies on 4 faces hope it helps

5 0
3 years ago
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