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Natasha2012 [34]
3 years ago
8

How do I find the value of x

Mathematics
1 answer:
juin [17]3 years ago
8 0
You set (x+15) equal to 40 and solve for x.

x+15=40
  -15   -15

x=25

Hope this helps!
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Can someone help me with this?​
Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

Sum =  \frac{a( {r}^{n} - 1) }{(r - 1)}   \\

So,

\frac{a( {r}^{n} - 1)}{(r - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{(3 - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{2}  = 728 \\  {3}^{n}  - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n}  = 729 \\  {3}^{n}  =  {3}^{6}  \\ \boxed{ n = 6}

Therefore, number of terms is 6

  • 6 is the right answer.
3 0
2 years ago
What is the equation of a line, in general form, that passes though points (-1,2) and (5,2)?
Tom [10]

Answer:

A

Step-by-step explanation:

To write the equation of the line. first calculate the slope using the slope formula.

m = \frac{y_2-y_1}{x_2-x_1} = \frac{2-2}{5--1}= \frac{0}{6} = 0

Since the slope of this line is 0, it is horizontal and has the form y=b where b is the y-coordinate. So y = 2 is the equation. In general form, it would be y-2 = 0

3 0
3 years ago
Determine the values of x on which the function f(x)=2x^2-x-15/4x^2-12x is discontinuous and verify the type of discontinuity at
melomori [17]
<span>Determine the values of x on which the function f(x)=2x^2-x-15/4x^2-12x is discontinuous and verify the type of discontinuity at each point.

A.There is a vertical asymptote at 0 and a hole at 3.
B.There are vertical asymptotes at -5/2 & 0 and a hole at 3.
C.There is a vertical asymptote at 3 and a hole at 0.
D.There are vertical asymptotes at 0 & 3.
</span>
Result:
(-7/4)x^2-13x

The roots are:
x= -52/7
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See attached pictures.

6 0
3 years ago
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Eduardwww [97]
The middle term is -x
4 0
3 years ago
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galben [10]

Answer:

The answer is B. 1

Step-by-step explanation:

rise over run

1/1=1

4 0
2 years ago
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