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seropon [69]
3 years ago
14

8 cm10 cm3 cmWhat is the volume of the right rectangular prism?​

Mathematics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

240 cubic centimetres

Step-by-step explanation:

volume of the right rectangular prism

= 8 \times 10 \times 3 \\  = 240 \:  {cm}^{3}

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Which picture has a line of symmetry
Arturiano [62]
Add the picture pls
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Harry and Selma start driving from the same location. Harry drives 42 miles north while Selma drives 144 miles east. How far apa
weqwewe [10]
186 Miles. Just add 144+42=186 Miles.
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7 times as much as sum of 1/3 and 4/5
Salsk061 [2.6K]
So the formula is
7*(1/3+1/5) = x

First find the common denominator of the fractions.  In this case the common denominator of 3 and 5 is 15 so we must convert them to 15ths.  To do that we divide 15 by the denominator and take that answer and multiply the numerator by it.

So for 1/3 we take 15/3(denominator) = 5 and multiply the numerator (1) by it

5 * 1 = 5 so 1/3 converts to 5/15

Do the same for 1/5 we take 15/5 = 3 and multiply the numerator (4) by it

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Now we add 5/15 and 12/15 = 17/15 so we have our formula now to

7*17/15

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8 0
3 years ago
Read 2 more answers
The product of Greg’s age and 2 is 26
Goshia [24]

Answer:

Gregs age is 13

Step-by-step explanation:

13 + 13 = 26

which is equivalent to 13 × 2 = 26

5 0
3 years ago
2. Solve the equation using the quadratic<br> formula.<br> -4x2 + 40x + 16 = 0<br> Page 1 of 2
kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

<em><u>Solution:</u></em>

Given equation is:

-4x^2 + 40x + 16 = 0

To find: solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16

<u><em>Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,</em></u>

\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0
3 years ago
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