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marysya [2.9K]
3 years ago
8

a hairstylist schedules 1/4 hour to trim a customers hair and 1/6 hour to style the customers hair. the hairstylist plans to wor

k 3 1/3 hours each day for 5 days each week. how many appointments can the hairstylist schedule each week if each customer must be trimmed and styled? (show work)
Mathematics
1 answer:
spin [16.1K]3 years ago
4 0
So a trim lasts 1/4*60=15 minutes and a style lasts 1/6*60=10 minutes.
If we add these together, 15+10=25 minutes that is how long each customer takes.
In one day she works for 3 1/3*60=200 minutes in total, so can fit in 200/25=8 appointments per day.
So in 5 days she can have 8*5=40 total appointments each week.
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A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.
vichka [17]

Answer:

14878.04878miles/hours^2

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

A=(Vf-Vi)/T where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

A=(65miles/hour - 6miles/hour)/14.8seconds, but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)

X=0.0041hours

Using X=0.0041hours in the previous equation instead of 14.8seconds we  have:

A=(65miles/hour - 6miles/hour)/0.0041hours

A=(61miles/hour)/0.0041hours

A=(61miles)/(hour*0.0041hours)

A=61miles/0.0041hours^2

A=14878.04878miles/hours^2

In conclusion, the acceleration rate is 14878.04878miles/hours^2

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3 years ago
I need help solving number 11 please.
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Find the area of a 120° sector of a circle whose radius is 6.
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First, determine the area of the whole circle by the equation, A = πr². Substituting,
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Then, multiply this value with the ratio of the given angle to the whole revolution,
                            A(sector) = 36π x (120° / 360°)
The area of the sector is therefore 12π units².
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Answer: 32 + 27 = 59

Step-by-step explanation:

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Step-by-step explanation:

\text{Use}\ (a^n)^m=a^{nm}\\\\(2^3)^5=2^{3\cdot5}=2^{15}

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