Let
x-------------> first odd integer
x+2---------> second odd integer
x+4---------> third odd integer
we know that
(x)+(x+2)+(x+4)=201--------> 3x+6=201--------> 3x=195-------> x=65
the three <span>sides of triangle RIO are
</span>x=65 in
x+2-----> 65+2-----> 67 in
x+4----> 65+4------> 69 in
then
69²=4761----------> c²
(65²+67²)=8714--------> a²+b²
c² < (a²+b²)---------> the triangle RIO is not obtuse
Is acute angle triangle
<span>statements
1) </span><span>The triangle is obtuse--------> is false
</span>Is acute angle triangle
<span>
2) </span><span>The triangle is scalene-----> is correct
The three sides measures are diferent
3)</span><span>The smallest side measures 61 inches--------> is false
</span><span>The smallest side measures 65 in
</span><span>
4)</span><span>The largest side measures 69 inches-------> is correct
</span><span>
5) </span><span>If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller
</span><span>If triangle RIO is dilated of 1/3, then news sides are
</span>65/3------> 21.67 in
67/3-------> 22.33 in
69/3------> 23 in
the new perimeter is=21.67+22.33+23------> 67 in
201-67=134 in
therefore
If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller----------> is false
Because the perimeter of the dilated triangle will be 134 units smaller
Answer:
Step-by-step explanation:
y-3=1/2(x-0)=1/2 x
2y-6=x
2y-x=6
The correct statement comparing the theoretical and experimental probabilities is given as follows:
.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
The theoretical probability is taken before any experiment. Since the four sections are equal, the theoretical probability is:
T(H) = 1/4.
The experimental probability is taken considering previous experiments. Out of 100 tosses, 28 landed on H, hence:
E(H) = 28/100 = 7/25.
Hence the correct statement is:
.
More can be learned about probabilities at brainly.com/question/14398287
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Since the area of the circle is only 3.14. that means 3.14 out of one hundred units can be hit. so you have a 3.14% chance of hitting the circle in the middle. SO the probability is very close to 0.
100 - 3.14 = 96.86, so we have a 97 percent chance (approximately) of landing in the white space, This is very close to one.