Answer:
The most appropriate value of the critical value is 2.289.
Step-by-step explanation:
We are given that a researcher takes a random sample of 41 bulbs and determines that the mean consumption is 1.3 watts per hour with a standard deviation of 0.7.
We have to find that when constructing a 97% confidence interval, which would be the most appropriate value of the critical value.
Firstly, as we know that the test statistics that would be used here is t-test statistics because we don't know about the population standard deviation.
So, for finding the critical value we will look for t table at (41 - 1 = 40) degrees of freedom at the level of significance will be
.
Now, as we can see that in the t table the critical values for P = 1.5% are not given, so we will interpolate between P = 2.5% and P = 1%, i.e;

So, the critical value at a 1.5% significance level is 2.289.
Answer is D. for every 1 small mouth caught, it is estimated you will catch 3 largemouth bass
The probability that a randomly selected student is in music/drama is 25%
<h3>How to determine the probability?</h3>
From the table, we have the following values
Music/Drama = 7 + 13 + 5 = 25
Total = (20 + 20 + 25 + 7 + 13 + 5 + 3 + 2 + 5) = 100
The probability is then calculated as:
P = Music/Drama / Total
So, we have:
P = 25/100
Express as percentage
P = 25%
Hence, the probability that a randomly selected student is in music/drama is 25%
Read more about probability at:
brainly.com/question/251701
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First term (a) = -15
common difference(d)= -9-(-15)
= -9+15=6
So,
12th term(a12)= a +(n-1)d
= -15+(12-1)×6
= -15 + 11×6
= -15+66
= 51
Answer:
(x+9,y-12)
Step-by-step explanation:
sorry if this didnt help