Answer:
the minimum length of the first piece is 4 feet
Answer:
10 inches
Step-by-step explanation:
Assuming a rectangular tile
P = 2(l+w) where l is the length and w is the width
P = 2(1+4)
= 2(5)
= 10 inches
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
Answer:
5secs
Step-by-step explanation:
Given the equation of the height expressed ad;
h(t) = - 16t^2 + initial height
Given that initial height = 400feet
h(t) = - 16t^2 + 400
The waste will hit the ground at when h(t) = 0
substitute
0 = - 16t^2 + 400
16t^2 = 400
t² = 400/16
t² = 25
t = √25
t = 5secs
Hence it will take the easte 5secs to hit the ground
