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Kobotan [32]
2 years ago
6

Daom its been so long i was just zoning out and thinkin... why havent they made a dark mode to this smh i be on discord to much

my eyes have adjusted
btw who invented the first algebra term?
Mathematics
1 answer:
Alenkasestr [34]2 years ago
5 0

Answer:

dark mode da best

Step-by-step explanation:

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The surface of An air hockey table has an area of 40 ft. Perimeter is 28 feet what are the dimension of the air hockey table
sukhopar [10]

Answer:

4ft and 10ft

Step-by-step explanation:

you got to figure out which 2 numbers when multipled make 40 and when added make and then multiplied by 2 make 28

5 0
2 years ago
Will give brainliest ! need help due in an hour
bekas [8.4K]
If I’m not mistaken your years are going to be the x value and the cases are your y values so type the year as the x value and type the number of cases as the y value Let me know if I was right
5 0
3 years ago
Which of the following can be construed using the folding method below ?
jeka57 [31]
Do you av options, Because i need to see the folding method 
4 0
3 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
A Cashier has fifteen $5 bills . How Much does he have in $5 bills
Mila [183]
Lets make a known and an unknown chart:

KNOWN: Fifteen $5 bills.

UNKNOWN: How much is that?

So to find the answer to this, we are going to do 5+5+5+5+5+5+5+5+5+5+5+5+5+5+5=??
The answer is $75.
~Hope I helped!~
4 0
3 years ago
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