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Yuliya22 [10]
3 years ago
15

The equation y=ax describes the graph of a line.if the value of a is positive,the line

Mathematics
2 answers:
ahrayia [7]3 years ago
5 0
If the value of a is positive, the line slopes upwards.
bekas [8.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

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Please help me with this ​
MissTica

Answer:

For the question on the right, I assume b is the exponential factor, or growth factor.

Step-by-step explanation:

Linear:

Y=aX + b\\(X, Y) = (0, 15) => b = 15\\(X,Y) = (1, 12) => a = -3\\Y = -3X + 15

You can find the equation by using two points and the equation for a line.

Exponential:

Y = a^{bX+c}\\(X, Y) = (0, 81) => a^{c} = 81 => a^{c} = 3^{4} => a=3, c=4\\(X, Y) = (1, 27) => a^{b+c} = 27 => a^{b}a^{c} = 27 => a^{b} = \frac{27}{81} = \frac{1}{3} => b=-1\\Y = 3^{-X+4}

6 0
2 years ago
A driving exam consists of 30 ​multiple-choice questions. Each of the 30 answers is either right or wrong. Suppose the probabili
Butoxors [25]

Answer:

a. P(x>20)=0.19

b. P(x≥6)=0.72

c. P(x≤20)=0.81

d. A and C

Step-by-step explanation:

We know that:

1) the probability that a student makes fewer than 6 mistakes is 0.28

P(x

2) The probaiblity that a student makes between 6 to 20 mistakes is 0.53.

P(6\leq x\leq20)=0.53

We will express the proabilibities in function of the information we have.

a. Probability that a student makes more than 20 mistakes.

P(x>20)=1-P(x\leq20)=1-(P(x20)=1-(0.28+0.53)=1-0.81=0.19

b. Probability that the student make 6 or more mistakes

P(x\geq6)=1-P(Px

c. Probability that a student makes 20 mistakes at most

P(x\leq20)=P(x

d. A and C, because A takes a event of more than 20 mistakes and C takes the event of 20 or less mistakes. Both events cover a probability of 1.

7 0
3 years ago
A. X=3 m<br> B. X=5 m<br> C. X=6 m<br> D. X=9 m
enyata [817]

Answer:

ok so we can divide 15 by 5 to get 3

so we know the building is 3 times bigger

so we multiply 3 by 3 to get 9

so the answer is D

8 0
3 years ago
Read 2 more answers
Can someone help me here<br><br> NONSENSE=REPORT​
lys-0071 [83]

\huge \qquad \sf \: Answer

Here we go ~

1. A circle can be named by their Centre, so here in the diagram it's :

  • Circle A

2. Name 4 radii :

Radii are the line segments that joins the centre and boundary of circle.

They are :

  • FA
  • GA
  • BA
  • CA

3. 2 Major arcs :

considering two points on a circle, and joining them forms a curve ( you can say part of circumference )

When we consider two points two arcs are formed and the arc with more length is known as Major Arc

That is :

  • Major arc ECF
  • Major arc BEC

4. A Semicircle :

Semicircle is special arc which is formed when two arcs formed by the points are equals to one another... it's also half the Perimeter of circle.

that is :

  • Arc CF is a Semicircle

5. 3 minor arcs :

The arc formed by two points having lesser length is known as minor arc.

that is :

  • Arc EF
  • Arc BG
  • Arc FG

6. 3 Central angles :

Central angles are angles formed by arcs on centre of the circle ~

that is :

  • Angle FAB
  • Angle BAC
  • Angle GAB

7. A diameter :

Diameter is a chord that passes through centre of the circle.

  • CF

8. Congruent Angles :

In the given figure, there are two equal/congruent angles that are ~

  • Angle BAG and Angle GAF

9. Adjacent arcs :

The arcs that have one common end point are known as Adjacent arcs ~

that are :

  • Arc FG and Arc GB

4 0
2 years ago
Read 2 more answers
Please help and thank you
kondaur [170]

Answer:

Step-by-step explanation:

Let's see how well I can explain this. \frac{\pi}{6} is the same as a 30 degree angle which is in quadrant 1. If you picture the unit circle, right in the center of it is the origin. If you draw a straight line from 30 degrees and through the center (the origin), you will automatically "connect" with the reference angle of 30 (this is true for ALL angles on the unit circle). This puts us in quadrant 3. In quadrant 3, x is negative and so is y. So the terminal point of the reference angle for 30 degrees has the same exact values, but both of them are negative (again, because both x and y are negative in quadrant 3). I can't see your choices but the one you want looks like this:

(-\frac{\sqrt{3} }{2},-\frac{1}{2})

3 0
3 years ago
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