1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
julsineya [31]
3 years ago
9

Solve for x. 15x + 6 = 10x + 21 x = -5 x = 5 x = 3 x = 5

Mathematics
1 answer:
klio [65]3 years ago
4 0
Move all the x terms to one side and solve for x. 15x-10x=21-6 : 5x/5=15/5 : x=3
You might be interested in
Help?????............
GREYUIT [131]
I’m not really for sure...but
I’d say it’s
x is negative and y is negative

Hope I’m Correct Sorry If I’m Not :)
5 0
2 years ago
Read 2 more answers
Name of devices is used for drawing curves which can't be drawn by a compass<br>​
Snowcat [4.5K]
A protractor can be used!
6 0
3 years ago
Three farmers can reap a field in 6 hours. The owner wants the field to be reaped in 1 hour. How many farmers should he have wor
kkurt [141]

Answer:

18 men are required to reap the field in 1 hour

Step-by-step explanation:

3*6=18

3 0
2 years ago
42 liters of juice were evenly
I am Lyosha [343]

Answer: 42/6=7

Step-by-step explanation:

there's 42 liters of juice right? so to <u>divide</u> it into six batches all you got to do is divide all the liters of juice into how many batches you need. So as it says in the question, just divide 42 by 6 and you'll get your answer which is 7.

5 0
2 years ago
Read 2 more answers
Let X1 and X2 be independent random variables with mean μand variance σ².
My name is Ann [436]

Answer:

a) E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu

So then we conclude that \hat \theta_1 is an unbiased estimator of \mu

E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu

So then we conclude that \hat \theta_2 is an unbiased estimator of \mu

b) Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}

Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}

Step-by-step explanation:

For this case we know that we have two random variables:

X_1 , X_2 both with mean \mu = \mu and variance \sigma^2

And we define the following estimators:

\hat \theta_1 = \frac{X_1 + X_2}{2}

\hat \theta_2 = \frac{X_1 + 3X_2}{4}

Part a

In order to see if both estimators are unbiased we need to proof if the expected value of the estimators are equal to the real value of the parameter:

E(\hat \theta_i) = \mu , i = 1,2

So let's find the expected values for each estimator:

E(\hat \theta_1) = E(\frac{X_1 +X_2}{2})

Using properties of expected value we have this:

E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu

So then we conclude that \hat \theta_1 is an unbiased estimator of \mu

For the second estimator we have:

E(\hat \theta_2) = E(\frac{X_1 + 3X_2}{4})

Using properties of expected value we have this:

E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu

So then we conclude that \hat \theta_2 is an unbiased estimator of \mu

Part b

For the variance we need to remember this property: If a is a constant and X a random variable then:

Var(aX) = a^2 Var(X)

For the first estimator we have:

Var(\hat \theta_1) = Var(\frac{X_1 +X_2}{2})

Var(\hat \theta_1) =\frac{1}{4} Var(X_1 +X_2)=\frac{1}{4} [Var(X_1) + Var(X_2) + 2 Cov (X_1 , X_2)]

Since both random variables are independent we know that Cov(X_1, X_2 ) = 0 so then we have:

Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}

For the second estimator we have:

Var(\hat \theta_2) = Var(\frac{X_1 +3X_2}{4})

Var(\hat \theta_2) =\frac{1}{16} Var(X_1 +3X_2)=\frac{1}{4} [Var(X_1) + Var(3X_2) + 2 Cov (X_1 , 3X_2)]

Since both random variables are independent we know that Cov(X_1, X_2 ) = 0 so then we have:

Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}

7 0
3 years ago
Other questions:
  • Question 2
    11·2 answers
  • At a fixed operating setting, the pressure in a line downstream of a reciprocating compressor has a mean value of 950 kPa with a
    12·1 answer
  • Help me please!!!! What percent of data is above the 38?
    8·2 answers
  • Given the functions =−12 (2)x+3. Select all statements that are true.
    11·1 answer
  • SOMEONE HELPPP MEEE OUTTT PLEASEEEE!!!
    10·2 answers
  • Is the unit 4,872 ones, tenths, or hundredths?
    14·1 answer
  • List five common multiples for 8 and 14​
    10·2 answers
  • If a quadratic has x-intercepts at (-1,0) and (6,0), what would be the factored form of the equation?
    5·1 answer
  • Which expression is equivalent to 4^7x 4-^5
    15·1 answer
  • Find the distance between the two points in simplest radical form.<br> (-5,0) and (-9,9)
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!