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3 years ago

Solve for x. 15x + 6 = 10x + 21 x = -5 x = 5 x = 3 x = 5

Mathematics

1 answer:

klio [65]3 years ago

4 0

Move all the x terms to one side and solve for x. 15x-10x=21-6 : 5x/5=15/5 : x=3

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I need to work out x

frutty [35]

Answer:

9,765 cm

Step-by-step explanation:

We'll solve out the measurements for triangle ABC then it will be easy to figure out x

For triangle ABC, we have

Angle B = 90 degrees.

Angle A (CAB) = 38 degrees (the angle CAD is 19 and is said to be half of CAB, since the line AD is a bisector).

Angle C = 180 - 90 - 38 = 52 degrees.

To find the measurement of the BC line, which we label a, we know that

$\frac{a}{sin(A)} = \frac{c}{sin(c)}$

So, we can isolate the a to get:

$a = \frac{c * sin(A)}{sin(c)} = \frac{25 * sin(38)}{sin(52)} = 19.53$

Now we know the segment BC is 19.53 cm.

And we know that segments CD and DB are equal, since AD is a bisector, cutting the CAB angle in half.

So, CD is half of BC.... so 19.53 / 2 = 9.765 cm

7 0

3 years ago

2 and 1/4 cups equals how many pints? WILL MARK BRAINILEST!!! IF CORRECT

Mumz [18]

The answer is 1.125 liquid pints

7 0

3 years ago

Tickets for the school concert were 3$ and 2$. If 245 tickets were sold for a total of $630, how much of each kind were sold?

Hatshy [7]

2x + 3y = 630
x + y = 245 then you want to get rid of x so in the second equation × by -2 and get -2x -2y =-490 subtract this equation from the first to get y=$140 substitute 140 in for y and get x= $105 and 2x=210 and 3y=420 210 +420=630

7 0

3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

11r+7s what is the answer please help!

Tasya [4]

That is the answer. you can't simplify it.

7 0

3 years ago