Solve the equation 6x12=4x-18

Mdcxxxvi in Roman numerals

klasskru [66]

That's Roman numerals but it is 1636 not as Roman numerals hope I helped

6 0

3 years ago

Read 2 more answers

Please help its inequalities 2x < 6

Katyanochek1 [597]

$x < 3$
hope it helps

4 0

3 years ago

Maya runs a farm stand that sells raspberries and blueberries. Each pound of raspberries sells for $1 and each pound of blueberr

aniked [119]

30 pounds of raspberries and 50 pounds of blueberries are sold

Solution:

Let "a" be the pounds of raspberries sold

Let "b" be the pounds of blueberries sold

Cost per pound of raspberry = $ 1

Cost per pound of blue berry = $ 3.25

Maya made $192.50 from selling a total of 80 pounds of raspberries and blueberries

Therefore,

a + b = 80

a = 80 - b ------- eqn 1

Maya made $192.50. Therefore, frame a equation as:

pounds of raspberries sold x Cost per pound of raspberry + pounds of blueberries sold x Cost per pound of blue berry = 192.50

$a \times 1 + b \times 3.25 = 192.50$

a + 3.25b = 192.50 ------ eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

80 - b + 3.25b = 192.50

2.25b = 192.50 - 80

2.25b = 112.5

Divide both sides by 2.25

b = 50

Substitute b = 50 in eqn 1

a = 80 - 50

a = 30

Thus 30 pounds of raspberries and 50 pounds of blueberries are sold

3 0

3 years ago

kins age is twice that of her sister when you add kims age to her sisters you get 24 how old is each sister (a)write a equation

zimovet [89]

Kim's age is twice of that of her sister. We'll let k2 = Kim and k = Kim's sister.

So, k2. When you add Kim's age to her sister age you get 36.

Because Kim is twice the age of her sister k2. And because it said 'add' then we put a + sign. k2 + s = 36. Now let's solve it.

k2 + k = 36 < Given

3k = 36 < Combine like terms

k = 12 < Divide both sides by 3

We know Kim's sister is 12 y/o but what about Kim herself? Earlier we assigned Kim to k2. Substitute 12 for k and you get 12(2) = 24

Kim's sister is 12 y/o and Kim is 24 y/o

Please give Brainliest!

8 0

3 years ago

Read 2 more answers

Use the compound interest formulas A= P (1 + r/n) ^nt and A= Pe ^ rt to solve the problem given. Round to the nearest cent. Find

Dennis_Churaev [7]

Answer:

$\$30,460$
$\$30,497$
$\$30,522$
$\$30,535$

Step-by-step explanation:

We know that,

$A=P\left (1+\dfrac{r}{n}\right )^{n\cdot t}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

n = Number of times interest is compounded per year,

t = time period in year.

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded semiannually

Here,

P = $25,000

r = 5% = 0.05

n = 2 (as compounded semiannually)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{2}\right )^{2\times 4}$

$=25000\left (1+0.025\right )^{8}$

$=25000\left (1.025\right )^{8}$

$=\$30,460$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded quarterly.

Here,

P = $25,000

r = 5% = 0.05

n = 4 (as compounded quarterly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{4}\right )^{4\times 4}$

$=25000\left (1+0.0125\right )^{16}$

$=25000\left (1.0125\right )^{8}$

$=\$30,497$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded monthly.

Here,

P = $25,000

r = 5% = 0.05

n = 12 (as compounded monthly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{12}\right )^{12\times 4}$

$A=25000\left (1+\dfrac{0.05}{12}\right )^{48}$

$=\$30,522$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded continuously.

$A= Pe^{rt}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

t = time period in year.

Putting all the values,

$A= 25000e^{0.05\times 4}=\$30,535$

It can be observed that, the frequent we compound the amount, the more we get.

7 0

3 years ago