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Sketch a right
triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x”
and assigning angle “a” as the angle between A and H. Using Pythagorean theorem,
you will get “square root of x-squared minus 9” as the opposite side (O). Using
SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) =
x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side
over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the
algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.
Answer:
Step-by-step explanation:
1). 10 = 
10(7 + x) = 1 + 7x
70 + 10x = 7x + 1
10x - 7x = 1 - 70
3x = -69
x = -23
2). 0.2 = 
0.2(12 + x) = 6 + 2x
2.4 + 0.2x = 6 + 2x
2.4 - 6 = 2x - 0.2x
1.8x = -3.6
x = -2
3). 0.8 = 
0.8(x + 0.5) = x
0.8x + 0.4 = x
x - 0.8x = 0.4
0.2x = 0.4
x = 2
4). 3.5 = 
3.5(0.5 - x) = 4 + 2x
1.75 - 3.5x = 4 + 2x
-3.5x - 2x = 4 - 1.75
-5.5x = 2.25
x = -
x = - 
Are you trying to find n?
Answer:
No
Step-by-step explanation:
