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bagirrra123 [75]
3 years ago
9

Geometry question, need major help

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

5

Step-by-step explanation:

Each triangle is a myriad of both |, ||, and |||.

Because BE = || and FE = ||| then BF = |

CD = 10 but thats equal to 2 | meaning that 1 | is 5.

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The point of intersection is at (0,2)
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The remains of an ancient ball court include a rectangular playing alley with a perimeter of about 24m. The length of the alley
allsm [11]

ANSWER

Length of the playing alley = 9m

Width of the playing alley = 3m

STEP-BY-STEP EXPLANATION:

Given information

<em>The perimeter of a rectangular playing alley = 24 m</em>

<em>The length of the alley is three times the width</em>

Let l represents the length of the alley

Let w represents the width of the alley

Step 1: Write the formula for calculating the perimeter of a rectangle

\text{Perimeter of a rectangle = 2(l + w)}

Where l is the length and w is the width of the rectangle

Recall, length = 3 times the width of the alley

Mathematically,

\begin{gathered} l\text{ = 3 }\times\text{ w} \\ l\text{ = 3w} \end{gathered}

Step 2: Substitute the value of l = 3w into the above formula

\begin{gathered} P\text{ = 2(l + w)} \\ p\text{ = 24m} \\ l\text{ = 3w} \\ 24\text{ = 2(3w + w)} \end{gathered}

Step 3: Solve for w

\begin{gathered} 24\text{ = 2(4w)} \\ 24\text{ = 8w} \\ \text{Divide both sides by 8} \\ \frac{24}{8}\text{ = }\frac{8w}{8} \\ w\text{ = 3 m} \end{gathered}

From the calculations above, you will see that the width of the playing alley is 3m

Step 4: Solve for l

\begin{gathered} \text{Recall, l = 3w} \\ w\text{ = 3} \\ l\text{ = 3 }\times3 \\ l\text{ = 9m} \end{gathered}

Hence, the length of the playing alley is 9m

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2 years ago
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for each numerator:

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second one:

10 (c.d.) : 2 (denominator) = 5

5 * 1 (numerator) = 5

The fractions are 4/10 and 5/10

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3 years ago
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Volgvan

Answer:

-8

Step-by-step explanation:

<em>Solve </em><em>the </em><em>brackets</em><em> </em><em>first</em>

<em>4</em><em>/</em><em>2</em><em>x</em><em>+</em><em>2</em><em>8</em><em>=</em><em>1</em><em>2</em>

<em>then </em><em>group </em><em>the </em><em>like</em><em> terms</em>

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<em>2</em><em>x</em><em>/</em><em>2</em><em>=</em><em>-</em><em>1</em><em>6</em><em>/</em><em>2</em>

<em>x=</em><em> </em><em>-</em><em>8</em>

<em>i</em><em> </em><em>hope </em><em>this </em><em>helps</em>

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3 years ago
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lorasvet [3.4K]

Answer:

19

Step-by-step explanation:

Follow PEMDAS

4^2 + 6 ÷ 2

16 + 6 ÷ 2

16 + 3

19

4 0
4 years ago
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