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Andrew [12]
3 years ago
14

Pls help me with this problem:( and I’ll be happy if you write steps for this

Mathematics
1 answer:
andreev551 [17]3 years ago
4 0

Answer:

b/(b+a)

Step-by-step explanation:

(1/a)-(1/b) :[ (b²-a²)/ab²]

first  solve :

common denominator ab

(1/a)-(1/b)  = (b-a)/ab

[b-a/ab] : [(b²-a²)/ab²]

when divide fraction ( division sign turn to (×) and flip the second fraction(reciprocal):

[b-a/ab] × [ab²/ (b²-a²)]

then  simplify : ab²/ab = b

(b-a)×(b/b²-a²)    

factorize : b²-a² = (b-a)(b+a)

(b-a)×(b/(b-a)(b+a))  simplify : (b-a)/b-a = 1

[(b-a)(b)]/[(b-a)(b+a)

b/b+a

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C is the point (-301, 601)<br> Does C lie on the straight line passing through A and B?
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There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.

To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.

Step-by-step explanation:

Suppose the equation of the straight line that passes through E and F is this:

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10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.

If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.

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