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3 years ago

Pls help me with this problem:( and I’ll be happy if you write steps for this

Mathematics

1 answer:

andreev551 [17]3 years ago

4 0

Answer:

b/(b+a)

Step-by-step explanation:

(1/a)-(1/b) :[ (b²-a²)/ab²]

first solve :

common denominator ab

(1/a)-(1/b) = (b-a)/ab

[b-a/ab] : [(b²-a²)/ab²]

when divide fraction ( division sign turn to (×) and flip the second fraction(reciprocal):

[b-a/ab] × [ab²/ (b²-a²)]

then simplify : ab²/ab = b

(b-a)×(b/b²-a²)

factorize : b²-a² = (b-a)(b+a)

(b-a)×(b/(b-a)(b+a)) simplify : (b-a)/b-a = 1

[(b-a)(b)]/[(b-a)(b+a)

b/b+a

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Hunter-Best [27]

Assuming 1 is written rotationally symmetrical, using 0,1,6,8,9 to make numbers that have a degree of symmetry of 2 (i.e. 180 degrees), we can say

one digit numbers: 0,1,8

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(18 becomes 81, so not admissible, similarly for 19, 91,16,61, etc)

(00 is not considered generally as a two-digit number)

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101, 609, 808, 906,

replace the middle digit successively by 1 and 8 gives

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2 years ago

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Sergio039 [100]

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3 years ago

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ivann1987 [24]

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2 years ago

A cone and a cylinder both have a diameter of four feet and a height of six feet. Determine if the statement is true by selectin

Anettt [7]

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Step-by-step explanation:

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2 years ago

Y=4x-6 and passes through point 8,12

umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

$y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20$

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

$y=mx+b\\y=4x-20$

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

$y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14$

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

$y=mx+b\\y=-\frac{1}{4} x+14$

8 0

2 years ago