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zalisa [80]
3 years ago
11

Back to school is coming and laura is

Mathematics
1 answer:
sattari [20]3 years ago
7 0
Huh? Are you missing the something
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Just add a random answer
serg [7]
Thx ig lol how are u
8 0
3 years ago
What's the value of y
Keith_Richards [23]
Angle y is the same as 85 degrees
4 0
4 years ago
6.) the following function represents the profit P(n) in dollars that a concert promoter makes by selling tickets for n dollars
marissa [1.9K]
For Part A, what to do first is to equate the given equation to zero in order to find your x intercepts (zeroes)

0=-250n^2+3,250n-9,000 after factoring out, we get

-250(n-4)(n-9) and these are your zero values.

For Part B, you need to square the function from the general equation Ax^2+Bx+C=0. So to do that, we use the equated form of the equation 0=-250n^2+3,250n-9,000 and in order to have a positive value of 250n^2, we divide both sides by -1

250n^2-3,250n+9,000=0

to simplify, we divide it by 250 to get n^2-13n+36=0 or n^2-13n = -36 (this form is easier in order to complete the square, ax^2+bx=c)

in squaring, we need to apply <span><span><span>(<span>b/2</span>)^2 to both sides where our b is -13 so,
(-13/2)^2 is 169/4

so the equation now becomes n^2-13n+169/4 = 25/4 or to simplify, we apply the concept of a perfect square binomial, so the equation turns out like this 

(n-13/2)^2 = 25/4 then to find the value of n, we apply the square root to both sides to obtain n-13/2 = 5/2 and n is 9. This gives us the confirmation from Part A. 

For Part C, since the function is a binomial so the graph is a parabola. The axis of symmetry would be x=5.

</span></span></span>
7 0
4 years ago
Evaluate e/4+2f-3 when e=12 and f=1/2
levacccp [35]
12/4=3

2/2= 1

3+1=4-3=1
3 0
3 years ago
Read 2 more answers
A table has five bowls. None of the quantities in the bowls are prime, though the last two bowls are empty. Two of the quantitie
Digiron [165]

Since two of the quantities are squares and the sum of all of three is equal 21, then the possible values of those two quantities are: 1,4,9,16

Let's consider each possibility

1 and 4

21-1-4=16, but 16 is also square and there can be only two square so NO

1 and 9

21-1-9=11, but 11 is prime, so NO

1 and 16

21-1-16=4... 4 is a square ,so NO

4 and 9

21-4-9=8 , 8 is not prime and not a square, so YES

4 and 16

21-4-16=1, but 1 is a square ,so NO

9 and 16

9+16=25>21 so.. NO

<u>Therefore, the amounts in the first three bowls are 4,8,9.</u>

8 0
3 years ago
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