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MAXImum [283]
3 years ago
13

I need help on these three questions I’m so confused on how to answer them

Mathematics
1 answer:
GalinKa [24]3 years ago
8 0

Answer:

  1.  S(1) = 1; S(n) = S(n-1) +n^2

  2. see attached

  3. neither

Step-by-step explanation:

1. The first step shows 1 square, so the first part of the recursive definition is ...

  S(1) = 1

Each successive step has n^2 squares added to the number in the previous step. So, that part of the recursive definition is ...

  S(n) = S(n-1) +n^2

__

2. See the attachment for a graph.

__

3. The recursive relation for an arithmetic function is of the form ...

  S(n) = S(n-1) +k . . . . . for k = some constant

The recursive relation for a geometric function is of the form ...

  S(n) = k·S(n-1) . . . . . . for k = some constant

The above recursive relation is not in either of these forms, so it is neither geometric nor arithmetic.

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Solve the triangle.<br><br> B = 36°, a = 41, c = 20
svetoff [14.1K]

Answer:

See below

Step-by-step explanation:

When you have 2 sides and the angle between them you use the cosine theorem or law of cosines:

b^{2}=a^{2}+c^{2}-2acCos(B)

b^{2}=41^{2}+20^{2}-2(41)(20)cos36 \\b^{2}=1681 + 400-1327 \\b^{2}=754 \\b = 27.5

After you have a side and the opposed angle (side b and angle B), you use the law of sines:

\frac{a}{sinA} =\frac{b}{sinB}=\frac{c}{sinC}

I will calculate angle A first:

[tex]\frac{27.5}{sin36} =\frac{41}{sinA} \\sinA =\frac{41}{27.5} sin36 \\sin A = 0.876 \\A = 61.2\°[/tex]

Same for angle C:

\frac{27.5}{sin36} =\frac{20}{sinC} \\sinC =\frac{20}{27.5} sin36 \\sin C = 0.427 \\C = 25.3\°

The sum of the angles is 36° + 61.2° + 25.3° = 122.5°; The sum must be 180° so this isnt a triangle.

I re did the problem using B as 63° instead of 36° in case you wrote it wrong and I got a satisfactory answer.

using B = 36:

b = 36.6

angle A = 86.4°

angle C = 29.1°

A+B+C = 86.4° + 29.1° + 63° = 178.5° ~ 180°

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Step-by-step explanation:

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