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3 years ago

What is the prime factorization of 230

Mathematics

2 answers:

malfutka [58]3 years ago

4 0

2 X 5 X 23

this is the prime factorization of 230 :3

harina [27]3 years ago

3 0

The answer is simple just do 2 x 5 = 10 x 23 2 x 5 x 23

#simple

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How are adding and subtracting decimals different from multiplying decimals

statuscvo [17]

In bmultiplying, you always have to move the decimal of the product the amount of place values the decimal has in each factor, for example, 1.50 times 1.50= 2.25, the factors together have 4 decimals, so you move the decimal 4 times to the right (try it, it gets rid of alot of zeros in the answer.)

3 0

3 years ago

Read 2 more answers

There are three options for fans purchasing a band's new release CD. They can purchase the CD, a premium CD bundle, or a deluxe

cluponka [151]

Answer:

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

Step-by-step explanation:

Let c represents the number of CD's

Let d represents the number of deluxe bundles

Let p represents the number of premium bundles.

Now according to the given statement:

c = $15

d = c+2p =

d = 15+2p --------equation 1

455c+87p+35d = $12,845 --------equation 2

Now substitute the value of d in equation 2 to find the value of p

455c+87p+35d = $12,845

455(15)+87p+35(15+2p) = $12,845

6825+87p+525+70p=$12,845

Now combine the like terms:

6825+157p+525 = $12,845

Now shift all the like terms to the R.H.S

157p= 12845-6825-525

157p = 5495

Divide both sides by 157

157p/157 = 5495/157

p = 35

Now substitute the value p =35 in equation 1.

d = 15+ 2p

d = 15+2(35)

d = 15+70

d = 85

Therefore we have found that,

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

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3 years ago

Which of the following points is a solution of y > Ixl + 5?

Step2247 [10]

Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

$5 > |0|+5\\5> 0+5\\5 > 5$

5 IS NOT greater than 5, they are the exact same, so A is out.

Let's try B, 1 being x and 7 being y.

$7 > |1| + 5\\7 > 1 + 5\\7 > 6$

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

$1 > |7| + 5\\1>7+5\\1>12$

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of $y > |x|+5$ .

Hope this helped!

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3 years ago

Please help me. Somebody! I need help.

kogti [31]

Answer:

https://www.imsdb.com/scripts/Shrek.html

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4 years ago

What is the density of an object having a mass of 8.0 g and a volume of 25 cm655-02-05-00-00_files/i0020000.jpg?

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The answer is A. 0.32g/cm3

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3 years ago