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adelina 88 [10]
3 years ago
10

Is a product of two positive decimals, each less than 1, always less than each of the original decimals?

Mathematics
1 answer:
Elenna [48]3 years ago
6 0

Answer with explanation:

Let me answer this question by taking two decimals less than 1.

A= 0.50

B= 0.25

→A × B

= 0.50 × 0.25

=0.125

It is less than both A and B.

→→A=0.99

B= 0.1

→C=A × B

= 0.99 × 0.1

=0.099

It is less than both A and B.

So, We can say with surety, that if take two decimals ,both less than 1, the product of these two decimals will be  less than each of the original decimals.

General Rule

→A =0. p ,

→ B=0. 0 q,

Product of , A × B, gives a number in which  there will be three digits after decimal which will be always less than both A and B as in A, there is one digit after decimal, and in B there are two digits after decimal.

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The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and
mash [69]

Number of children attended is 1200 and number of adults attended is 1500

<h3><u>Solution:</u></h3>

Given that,

Admission fee for each children = $ 1.50

Admission fee for each adult = $ 4.00

Let "c" be the number of children attended

Let "a" be the number of adults attended

Given that 2700 people enter and $7800 is collected

Number of children attended + number of adults attended = 2700

c + a = 2700  -------- eqn 1

Also given that $7800 is collected

Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800

c \times 1.50 + a \times 4 = 7800

1.5c + 4a = 7800 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

From eqn1,

a = 2700 - c ----- eqn 3

Substitute eqn 3 in eqn 2

1.5c + 4(2700 - c) = 7800

1.5c + 10800 - 4c = 7800

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Therefore from eqn 3,

a = 2700 - 1200

a = 1500

Therefore number of children attended = c = 1200

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A restaurant stacked 7 pieces of wood on top of one another if each piece was 4/8 of a foot tall how tall was his pile
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His pile was 3 1/2 ft
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