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adelina 88 [10]
3 years ago
10

Is a product of two positive decimals, each less than 1, always less than each of the original decimals?

Mathematics
1 answer:
Elenna [48]3 years ago
6 0

Answer with explanation:

Let me answer this question by taking two decimals less than 1.

A= 0.50

B= 0.25

→A × B

= 0.50 × 0.25

=0.125

It is less than both A and B.

→→A=0.99

B= 0.1

→C=A × B

= 0.99 × 0.1

=0.099

It is less than both A and B.

So, We can say with surety, that if take two decimals ,both less than 1, the product of these two decimals will be  less than each of the original decimals.

General Rule

→A =0. p ,

→ B=0. 0 q,

Product of , A × B, gives a number in which  there will be three digits after decimal which will be always less than both A and B as in A, there is one digit after decimal, and in B there are two digits after decimal.

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Vesnalui [34]
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Water: h2o
Oxygen: o2

Water is h2o because there are 2 hydrogen molecules and 1 oxygen molecule.

h2 = 2 hydrogen molecules
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3 0
3 years ago
Given ; 2(10-13x)+9x=-34x+60
rewona [7]

Try comparing your solution with the following:

Solution:

2(10-13x)+9x=-34x+60\\(20-26x)+9x=-34x+60\\20-26x+9x=-34x+60\\20-17x=-34x+60\\20-60=-34x+17x\\-40=-17x\\x=\frac{40}{17}

Answer:

x=\frac{40}{17}

Check:

2[10-13(\frac{40}{17})]+9(\frac{40}{17})=-34(\frac{40}{17})+60\\-20=-20

<em>Hope this was helpful.</em>

3 0
3 years ago
f you ask Batman's nemesis, Catwoman, how many cats she has, she answers with a riddle: "Five-sixths of my cats plus seven." How
vovikov84 [41]
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3 0
3 years ago
Rosie buys 1/2 of a watermelon at the farmer's market. She shares it equally with her two best friends. 1/2 divided by 3. How mu
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7 0
3 years ago
Read 2 more answers
I really am confused on how to write a proof.
kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

\begin{gathered} AB=CD \\ BC=AD \end{gathered}

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

\begin{gathered} AE=CE \\ BE=DE \end{gathered}

Hence Proved.

8 0
1 year ago
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