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3 years ago

Is a product of two positive decimals, each less than 1, always less than each of the original decimals?

Mathematics

1 answer:

Elenna [48]3 years ago

6 0

Answer with explanation:

Let me answer this question by taking two decimals less than 1.

A= 0.50

B= 0.25

→A × B

= 0.50 × 0.25

=0.125

It is less than both A and B.

→→A=0.99

B= 0.1

→C=A × B

= 0.99 × 0.1

=0.099

It is less than both A and B.

So, We can say with surety, that if take two decimals ,both less than 1, the product of these two decimals will be less than each of the original decimals.

General Rule

→A =0. p ,

→ B=0. 0 q,

Product of , A × B, gives a number in which there will be three digits after decimal which will be always less than both A and B as in A, there is one digit after decimal, and in B there are two digits after decimal.

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1. What is a perfect square? 2. What is the square root of 4x²? 3. What is the square root of 25? 4. Factor 4x² + 20x + 25.

Ulleksa [173]

Answer:

Step-by-step explanation:

1) A perfect square is a whole number which is a product of a smaller whole number and itself. Examples of perfect squares are

4(2 × 2)

9(3 × 3)

16(4 × 4)

25(5 × 5)

36(6 × 6)

2) Square root of 4x² is 2x(product of square root of 4 and square root of x²)

3) square of 25 is 5

4) 4x² + 20x + 25

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 4

b = 20

c = 25

Therefore,

x = [- 20 ± √(20² - 4 × 4 × 25)]/2 × 4

x = [- 20 ± √(400 - 400)]/8

x = [- 20 ± 0]/8

x = - 20/8

x = - 2.5

3 0

3 years ago

The train clock run fast and gain 4 minutes every 3 days. How many minutes and seconds will it have gained at the end of 2 days.

Katarina [22]

Answer:

2 minutes, 40 seconds

Step-by-step explanation:

set up a proportion and cross-multiply:

4/3 = x/2

3x = 8

x = 2 2/3 which is 2 minutes, 40 seconds

8 0

3 years ago

Please can you answer it because I need the answer

andre [41]

Answer:

For x^2 + 5x - 14 = 0

x1= -7, x2 = 2

For x^2 + 5x + 6 = 0

x1 = -3, x2 = -2

Step-by-step explanation:

Pls see attached....

7 0

3 years ago

I will mark you. i need help fast thank you!

Ganezh [65]

Answer:

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Step-by-step explanation:

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3 years ago

I am having trouble with this relative minimum of this equation.<br>

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$