Question

What are the possible values of x if (4x-5)^2=49? check all that apply. -4/5, -1/2, 3, 5, 7

Answer 1

To solve an equation with a square yo would take the square root of both sides.
(4x - 5)^2 = 49
sqrt((4x - 5)^2) = sqrt49
4x - 5 = + - 7
4x - 5 = 7 and 4x - 5 = -7
4x = 12 4x = -2
x = 3 x = -1/2

Answer 2

The values are just 3 and -1/2 and that is all (: