Answer:
Speed of the river = 
km per hour
Step-by-step explanation:
Speed of the boat in still water = 4 km per hour
Let the speed of the river = v km per hour
Speed of the boat upstream = (4 - v) km per hour
Time taken to cover 6 km = 
= 
hours
Speed of the boat downstream = (4 + v) km per hour
Time taken to cover 12 km = 
hours
Since, time taken by the boat in both the cases is same,
6(4 + v) = 12(4 - v)
24 + 6v = 48 - 12v
12v + 6v = 48 - 24
18v = 24
v = 
v = km per hour
The domain of the composite function is given as follows:
[–3, 6) ∪ (6, ∞)
<h3>What is the composite function of f(x) and g(x)?</h3>
The composite function of f(x) and g(x) is given as follows:
In this problem, the functions are:
.
The composite function is of the given functions f(x) and g(x) is:
The square root has to be non-negative, hence the restriction relative to the square root is found as follows:
The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:
Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:
[–3, 6) ∪ (6, ∞)
More can be learned about composite functions at brainly.com/question/13502804
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Answer:
x = 0, π/4, π, 7π/4
Step-by-step explanation:
sin(2x) = √2 sin x
Use double angle formula.
2 sin x cos x = √2 sin x
Move everything to one side.
2 sin x cos x − √2 sin x = 0
Factor.
sin x (2 cos x − √2) = 0
Solve.
sin x = 0, cos x = ½√2
x = 0, π/4, π, 7π/4
Let the lengths of the east and west sides be x and the lengths of the north and south sides be y. the dimensions you want are therefore x and y.
The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y. We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.
The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128. Let's reduce this by dividing all three terms by 4: 2x + y = 32.
Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32. The formula for area is A = L * W. Solving 2x + y = 32 for y, we get y = -2x + 32.
We can now eliminate y. The area of the patch is (x)(-2x+32) = A. We want to maximize A.
If you're in algebra, find the x-coordinate of the vertex of this quadratic equation. Remember the formula x = -b/(2a)? Once you have calculated this x, subst. your value into the formula for y: y= -2x + 32.
Now multiply together your x and y values to obtain the max area of the patch.
If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero. This approach should give you the same x value as before; the corresponding y value will be the same; y=-2x+32.
Multiply x and y together. That'll give you the maximum possible area of the garden patch.
