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Andreas93 [3]
3 years ago
6

7(2x−a)−3(4x−a)−5(3x+2a)+a=0.

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Answer:

0

Step-by-step explanation:

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Show work too please :)
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5 0
3 years ago
0.99 divided by 1.1.
NeTakaya

Answer: 0.9

Step-by-step explanation:

6 0
2 years ago
Which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 + 2x – 1 into the quadratic formula bel
neonofarm [45]

Answer:

x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4(4)(negative 1) EndRoot Over 2(4) EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^2+bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^2-4ac} }{2a}

in this problem we have

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so

a=4

b=2

c=-1

substitute in the formula

x=\frac{-2(+/-)\sqrt{2^2-4(4)(-1)} }{2(4)}

therefore

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