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Kazeer [188]
3 years ago
12

n ΔABC, AB = 10 and BC = 5. Which expression is always true? A. 5 < AC < 10 B. AC = 5 C. 5 < AC < 15 D. AC = 10

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

A. 5 < AC < 10

Step-by-step explanation:

If ∆ABC is a right angled triangle, we use the Pythagoras formula:

c² = a² + b²

Where c = longest side

When given sides AB, AC and BC, the formula becomes:

AB² = AC² + BC²

Where AB = Longest side

In the question,

AB = 10 and BC = 5.

10² = AC² + 5²

AC² = 10² - 5²

AC² = 100 - 25

AC² = 75

AC = √75

AC = 8.6602540378

Therefore, the expression that is always true = A. 5 < AC < 10

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Answer:

\frac{x^3}{z^2}

Step-by-step explanation:

There are no given values, therefore we can't determine a definite answer. However, we are able to simplify the expression.

As we all know that any variable or number to the power of 0 is equal to 1. This means that y^0 = 1.

We also know that a negative power can bring the variable down and make it a fraction. This means that z^-^2=\frac{1}{z^2}

Now that we got these two sorted we are able to write it in a simplified form.

Answer: \frac{x^3}{z^2}

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C. Zero slope. If it's going straight up and down, there is no slope.
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Step-by-step explanation:

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Which Expressions are equivalent to:<br> 3(2/3p + 3 - 1/3p - 5)<br> Picture is provided
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Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)
vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

<em>Two angles are said to be supplementary when they add up to 180°.</em>

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

<em>Two angles are said to be complementary when they add up to 90°.</em>

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

<em>If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.</em>

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

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