4 to the 1st is 4
4 to the 2nd is 16
4 to the 3rd is 64
<span>4 to the 4th is 256
hope that helps</span>
Step-by-step explanation:
-1.7×-6 is the answer. Hope this helps.
Answer: Meaghan is right.
Step-by-step explanation:
For a number like:
123.45
the tens place would be the "2" (second number at the left of the decimal point)
The ones place would be the "3" (first number at the left of the decimal point)
Let's suppose that Lily is correct.
Then the quotient of:
43.61/7
Will be a number with two digits in the left of the decimal point.
The smallest number that meets this condition, is the number 10.
Then let's see:
7*10 = 70
then:
70/7 = 10
and:
43.61 < 70
(70 is larger than 43.61)
then:
43.61/7 < 70/7 = 10
Then:
(43.61/7) < 10
This means that our quotient is smaller than 10, then the first digit of the quotient can not be on the tens place.
Then Meaghan is the correct one.
We also could perform the quotient to find:
43.61/7 = 6.23
So yes, Meaghan is correct.
We solve this by the definition of slope in analytical geometry. The definition of slope is the rise over run. In equation, that would be
m = Δy/Δx = (y₂-y₁)/(x₂-x₁)
The x-coordinates here are the t values, while the y-coordinates are the f(t) values. So, let's find the y values of the boundaries.
At t=2: f(t)= 0.25(2)²<span> − 0.5(2) + 3.5 = 3.5
Point 1 is (2, 3.5)
At t=6: </span>f(t)= 0.25(6)² − 0.5(6) + 3.5 = 9.5
Point 2 is (6, 9.5)
The slope would then be
m = (9.5-3.5)/(6-2)
m = 1.5
Hence, the slope is 1.5. Interpreting the data, the rate of change between t=2 and t=6 is 1.5 thousands per year.
