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2 years ago

12

The points C,D,E and F all lie on the same line segment, in that order, such that the ratio of CD:DE:EF is equal to 1:6:3. If CF

=20, find EF

1 answer:

Rama09 [41]2 years ago

6 0

Answer:c

Step-by-step explanation:did

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Good Moring please please answers this

ira [324]

The answer will be reflect (2, - 3 ) in x = -1

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3 years ago

Can u proof it pls indeed help<br>ΑΔΒ = ΒΔΑ.

Contact [7]

Answer:

ΑΔΒ = ΒΔΑ because Δ stands for the difference between two numbers and the difference between two numbers doesn't change when switched to the other side.

6 0

3 years ago

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

2 years ago

Find the area of the shaded region. Round your answer to the nearest tenth. 9 m 20 9 m area aboutm? pls explain how.

Alenkinab [10]

Answer:

The area of the shaded region is 17.4 square meters.

Step-by-step explanation:

Since the shaded region in the center equals the remainders of a circle, the area of a square equals its side squared, and the area of a circle equals π times the radius squared, for To determine the area of the shaded region, the following calculations should be performed:

(9 ^ 2) - (π x (9/2) ^ 2) = X

81 - (π x 4.5 ^ 2) = X

81 - (3.141 x 4.5 ^ 2) = X

81 - 3.141 x 20.25 = X

81 - 63.6 = X

17.4 = X

Thus, the area of the shaded region is 17.4 square meters.

5 0

3 years ago

Super hero academy's ratio of boys to girls is 5:3. If 7th grade has 150,

UkoKoshka [18]

Answer:

94 boys and 56 girls.

Step-by-step explanation:

150/8 = 18.75 = x

b=x*5 = 94

g=x*3 = 56

b+g=150

8 0

2 years ago