Answer:
P(A) = 44.44%
P(B) = 50%
P(B|A) = 37.5%
P(B|A) different from P(B).
A and B are independent.
Step-by-step explanation:
If we have a total of 180 students, and 80 of them have a Playstation, we have that P(A) = 80/180 = 0.4444 = 44.44%
If we have 90 students that have a Xbox, we have that P(B) = 90/180 = 0.5 = 50%
If we have 30 students that have both consoles, we have that P(A and B) = 30/180 = 0.1667 = 16.67%
To find P(B|A), we will find for a student that has an Xbox inside the group of students that has a Playstation, that is, we have 30 students in a total of 80 students, so P(B|A) = 30/80 = 0.375 = 37.5%
P(B|A) is different from P(B), the first is 37.5% and the second is 50%, so events A and B are independent events.
There are 44 total small egg cartons, 264 / 6 = 44
There are 176 total medium egg cartons, (264 / 3) x 2 = 176
There are 44 total big egg cartons, 176 + 44 = 220
264 - 220 = 44
<u>Note: (So you don't get confused) Above is just the number of egg cartons, below is the number of eggs.</u>
There is a total of 352 eggs in the small egg cartons, 44 x 8 = 352
There is a total of 2112 eggs in the medium egg cartons, 176 x 12 = 2112
There is a total of 792 eggs in the large egg cartons, 44 x 18 = 792
Hope this Helps! :)
The logic is there are six sides to each die, so for each number on one die you can pair with six different numbers on the other die. Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12.
160 minus 147 is 13 13 over 160 multiplied by 100 equals 8.125 percent
0.9<span>% of </span>603<span> = 5.43
so estimated is 5.40</span>
