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Fudgin [204]
3 years ago
10

Factor the following polynomial written in standard form. B^2-14B+49

Mathematics
1 answer:
Vladimir79 [104]3 years ago
8 0

After factoring B^2-14B+49 we get (B-7)(B-7)

Step-by-step explanation:

We need to factorize the polynomial:

B^2-14B+49

Factorization is done by breaking the middle term such that the sum is equal to the middle value of polynomial and product is equal to product of first and last term in the polynomial.

So, Factorizing:

B^2-14B+49\\=B^2-7B-7B+49\\=B(B-7)-7(B-7)\\=(B-7)(B-7)

So, After factoring B^2-14B+49 we get (B-7)(B-7)

Keywords: Factorization, Factors

Learn more about factors at:

  • brainly.com/question/1464739
  • brainly.com/question/10771256

#learnwithBrainly

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babymother [125]

Answer:

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Step-by-step explanation:

The area of a square is the side length squared.

Let s be the side length:

s^2 = 70

s = \sqrt(70) = 8.4 in

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2 years ago
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butalik [34]

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Step-by-step explanation:

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PLEASE HELP!!!<br> Find the common difference for the arithmetic sequence. -55, -50, -45, -40.....
Fed [463]

Answer:

5

Step-by-step explanation:

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7 0
2 years ago
The graph is of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
Reika [66]

The real solutions of f(x) = 0 is; x = -8, 0 and 4

<h3>How to find the roots of a polynomial graph?</h3>

When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.

Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.

From the given graph, the real solutions are at x = -8, 0 and 4

Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4

Read more about Polynomial roots graph at; brainly.com/question/14625910

#SPJ1

8 0
1 year ago
Find the value of a and b if √5-1/√5+1=a+b√5
timurjin [86]

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Step-by-step explanation:

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